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jarptica [38.1K]
3 years ago
12

During a lesson in physical science about changes of matter, students made ice cream. among the materials that are required to m

ake ice cream is salt. which answer choice best explains the role of salt in this activity? adding salt to ice lowers the freezing temperature. this helps the milk mixture to freeze sooner because the mixture will reach the freezing temperature sooner. adding salt to the ice raises the freezing temperature. this helps the milk mixture to delay in freezing, giving the ice cream enough time to form and have a great taste. adding salt prevents the milk in the ice cream from going bad and giving the ice cream a bad taste. salt in ice cream preparation is used as a preservative to enable the ice cream to have a longer shelf life.
Physics
2 answers:
xxTIMURxx [149]3 years ago
8 0
A. <span>Adding salt to ice lowers the freezing temperature. This helps the milk mixture to freeze sooner because the mixture will reach the freezing temperature sooner.</span>
Tom [10]3 years ago
7 0

The answer is A. Have a nice day!

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A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = 0.27 J

Explanation:

Force = torque × length

Given

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length (L) = 5.91 cm  = 0.0591 m                         [Note 1 m = 100 cm ]

considering the formula above

          9.13 = k * 0.0591    where k denotes torque

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Energy Stored  = \frac{1}{2} k x^2

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8 0
3 years ago
Do the math: How many seconds would it take an echo sounder’s ping to make the trip from a ship to the Challenger Deep (10,994 m
Lera25 [3.4K]

Answer:

<h2>14.66secs</h2>

Explanation:

Given the formula for calculating the depth in metres expressed as

depth in meters = ½ (1500 m/sec × Echo travel time in seconds)

Given depth of the challenger = 10, 994 meters, we will substitute this given value into the formula given to calculate the time take for the echo to travel.

10, 994 = depth in meters = ½ * 1500 m/sec × Echo travel time in seconds

10,994 = 750 * Echo travel time in seconds

Dividing both sides by 750;

Echo travel time in seconds = 10,994 /750

Echo travel time in seconds ≈ 14.66secs (to two decimal places)

Therefore, it would take an echo sounder’s ping 14.66secs to make the trip from a ship to the Challenger Deep and back

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