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4 years ago

6

Which property remains unaffected during the rock cycle?

2 answers:

atroni [7]4 years ago

7 0

Which property remains unaffected during the rock cycle?

A. Texture of the rock.

B. Mass of the material.

C. Structure of the rock.

D. Compositions of the minerals

The answer is ( B ) Mass of material

aivan3 [116]4 years ago

6 0

the answer is B.) Mass of material.

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A plane designed for vertical takeoff has a mass of 8.0 × 10³ kg. Find the net work done by all forces on the plane as it accele

artcher [175]

Answer:

<em>the net work done after starting from rest is = 2.4 × 10⁵ J</em>

Explanation:

Work: Work can be defined as the product of force and distance. The fundamental unit of work is Joules (J), The unit of Energy is Joules (J), as such Energy and work are interchangeable during calculation, This is illustrated below

E = W = 1/2mv².......................... Equation 1

Where m = mass of the plane, v = velocity of the plane, E = Energy, W = work done.

v² = u² + 2as ................................. Equation 2.

Where v = final velocity of the plane, u = initial velocity of the plane, a = acceleration of the plane, distance of the plane.

<em>Given: a = 1.0 m/s², s = 30 m, u = 0 m/s (at rest)</em>

<em>Substituting these values into equation 2</em>

<em>v² = 0² +2×1×30</em>

<em>v² = 60</em>

<em>v = √60</em>

<em>v = 7.75 m/s</em>

Also given: m = 8.0 × 10³ kg, and v = 7.75 m/s

<em>Substituting these values into equation 1,</em>

<em>W = 1/2(8.0×10³)(7.75)²</em>

<em>W = (4.0×10³)(60)</em>

W = 240 × 10³ J

<em>W = 2.4 × 10⁵ J</em>

<em>Therefore the net work done after starting from rest is = 2.4 × 10⁵ J</em>

4 0

3 years ago

Another name for the skin as a whole.

sergejj [24]

Organ, integument, dermis

5 0

3 years ago

Calculate the mass of an 86kg object on the moon

Vikentia [17]

If an object that is 86kg on the moon then that is the answer, 86kg.

3 0

3 years ago

A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the

mylen [45]

Answer:

Angular acceleration, is $708.07\ rad/s^2$

Explanation:

Given that,

Initial speed of the drill, $\omega_i=0$

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, $\omega_f=28940\ rev/min=3030.58\ rad/s$

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

$\alpha =\dfrac{\omega_f}{t}\\\\\alpha =\dfrac{3030.58\ rad/s}{4.28\ s}\\\\\alpha =708.07\ rad/s^2$

So, the drill's angular acceleration is $708.07\ rad/s^2$ .

4 0

3 years ago

Select the correct answer.

anyanavicka [17]

<h2>MULTIPLE CHOICES</h2>

$\large\mathcal{QUESTION:}$

What is the basic unit of all matter?

$\large\mathcal{CHOICES:}$

OA neutron
OB. atom
OC. electron
OD. proton
OE. nucleus

$\large\mathcal{ANSWER:}$

B. Atom

_____

<u>Atom</u> is the smallest, <u>indivisible unit of a chemical</u> <u>element and the fundamental unit of matter</u>. It consists of a nucleus (neutrons + protons) surrounded by an electron cloud. The <u>atom</u> is the smallest unit of matter that cannot be divided chemically and is a building block with its own set of properties.

<h3>#ProvideUniqueAnswers</h3>

6 0

2 years ago