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3 years ago

10

Which grouping of the three phases of chlorine is listed in order from left to right for increasing distance between chlorine mo

lecules?
a. liquid, solid, gas?

1 answer:

GenaCL600 [577]3 years ago

8 0

Answer:
Solid, Liquid, Gas

Hope it helps! ^^

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What is the temperature difference if 300 cal are used to warm water

PIT_PIT [208]

Answer:

<u>The temperature difference is</u> $\frac{300}{m} Kkg^{-1}$

Explanation:

The formula that is to used is :

Δ $Q=ms$ Δ $T$

<em>where ,</em>

<em>Δ $Q$ is the heat supplied in calories = 300cal</em>
<em> $m$ is the mass of water taken = m (assumed)</em>
<em>Δ $T$ is the change in temperature</em>
<em> $s$ is the specific heat of water = $1calK^{-1}Kg^{-1}$ </em>

ΔT :

$\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}$

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3 years ago

State two conditions necessary for an esterification reaction to take place

nadya68 [22]

Explanation:

Esterification occurs when a carboxylic acid reacts with an alcohol. This reaction can only occur in the presence of an acid catalyst and heat. It takes a lot of energy to remove the -OH from the carboxylic acid, so a catalyst and heat are needed to produce the necessary energy.

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How does the chemical formula for the sulfite ion differ from the chemical formula for the sulfate ion?

VLD [36.1K]

Answer:

Sulfite contains 3 oxygens and sulfate contains 4 oxygens

Explanation:

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3 years ago

`Silver salts have antimicrobial properties--they can kill bacteria by interfering with certain proteins. Silver nitrate used to

Lostsunrise [7]

Answer:

3.6 × 10²⁴ atoms of O

Explanation:

Let's consider the molecular formula of silver nitrate: AgNO₃.

We can establish the following relations:

1 mol of AgNO₃ has 6.02 × 10²³ molecules of AgNO₃ (Avogadro's number).
1 molecule of AgNO₃ has 3 atoms of oxygen.

The atoms of oxygen in 2.0 moles of silver nitrate are:

$2.0molAgNO_{3}.\frac{6.02\times10^{23}moleculeAgNO_{3} }{1molAgNO_{3}} .\frac{3atomO}{1moleculeAgNO_{3}} =3.6\times10^{24}atomO$

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3 years ago

A metal crystallizes in a body-centered cubic unit cell. The radius of one atom = 2.30 x 10 -8 cm. The density of the metal is 0

maw [93]

Answer:

25.41 g/mol is molar mass of metal.

Explanation:

Number of atom in BCC unit cell = Z = 2

Density of metal = $0.867 g/cm^3$

Edge length of cubic unit cell= a = ?

Radius of the atom of metal = r = $2.30\times 10^{-8} cm$

$a=2\times r=2\times 2.30\times 10^{-8} cm=4.60\times 10^{-8} cm$

Atomic mass of metal =M

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density

Z = number of atom in unit cell

M = atomic mass

$(N_{A})$ = Avogadro's number

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

$0.867 g/cm^3=\frac{2\times M}{6.022\times 10^{23} mol^{-1}\times (4.60\times 10^{-8} cm)^{3}}$

$M = 25.41 g/mol$

25.41 g/mol is molar mass of metal.

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3 years ago