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elena55 [62]
3 years ago
7

Students in a chemistry class added 4g of magnesium(Mg) to 50g of hydrochloric acid (HCl). A chemical reaction occurred that pro

duced magnesium chloride (MgCl2) and 6g of hydrogen gas (H2).
Mg + HCl → MgCl2 + H2

What is the mass of the magnesium chloride produced?
A 4 g
B 50 g
C 54 g
D 48 g
Chemistry
1 answer:
GarryVolchara [31]3 years ago
7 0
C that shout be the answer
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dedylja [7]

Answer:

its TRUE

Explanation:

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7 0
3 years ago
As discussed in class, the Fischer esterification reactants and products are at equilibrium. How was the equilibrium of the reac
german

Answer:

See explanation

Explanation:

The particular reactants in the Fischer esterification reaction were not stated.

Generally, a Fischer esterification is a reaction that proceeds as follows;

RCOOH + R'OH ⇄RCOOR' + H2O

This reaction occurs in the presence of an acid catalyst.

We can shift the equilibrium of this reaction towards the products side in two ways;

I) use of a large excess of either of the reactants

ii) removal of one of the products as it is formed.

Any of these methods shifts the equilibrium of the Fischer esterification reaction towards the products side.

4 0
3 years ago
How many grams of CH4 will be in a 500ml contain at STP?
ArbitrLikvidat [17]

Answer:

Mass = 0.32 g

Explanation:

Given data:

Mass of CH₄ = ?

Volume of CH₄ = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Temperature = 273 K

Pressure = 1 atm

Solution:

Volume of CH₄:

500 mL (500 mL× 1L/1000 mL= 0.5 L)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm× 0.5 L = n×0.0821 atm.L/ mol.K  × 273 K

0.5 atm.L = n×22.4 atm.L/ mol

n = 0.5 atm.L / 22.4 atm.L/ mol

n = 0.02 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.02 mol × 16 g/mol

Mass = 0.32 g

7 0
3 years ago
Which is most likely water?​
svp [43]

Answer:

A

it looks like a liquid

Explanation:

4 0
3 years ago
Read 2 more answers
Gaseous ethane (CH,CH,) will react with gaseous oxygen (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H,0). Sup
BigorU [14]

<u>Answer:</u> The mass of CO_2 produced is 12.32 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For ethane:</u>

Given mass of ethane = 4.21 g

Molar mass of ethane = 30 g/mol

Putting values in equation 1, we get:

\text{Moles of ethane}=\frac{4.21g}{30g/mol}=0.140mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 31.9 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{31.9g}{32g/mol}=0.997mol

The chemical equation for the combustion of ethane follows:

2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O

By stoichiometry of the reaction:

If 2 moles of ethane reacts with 7 moles of oxygen gas  

So, 0.140 moles of ethane will react with = \frac{7}{2}\times 0.140=0.49mol of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, ethane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of ethane produces 4 moles of CO_2

So, 0.140 moles of ethane will produce = \frac{4}{2}\times 0.140=0.28mol of CO_2

We know, molar mass of CO_2 = 44 g/mol

Putting values in above equation, we get:

\text{Mass of }CO_2=(0.28mol\times 44g/mol)=12.32g

Hence, the mass of CO_2 produced is 12.32 g

7 0
3 years ago
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