Answer:
It's True...................
Given data
efficiency (η) = 65 %
= 0.65
Machine provides (Work done by the machine) = 1300 × 50
= 65000 J
efficiency (η) = work done by the machine ÷ work supplied to the machine
0.65 = 65000 ÷ Input work
Input work = 100000 J
= 100 KJ
The forces are the same like the third law of Newton states.I think
Answer:
1800J
Explanation:
Step one:
given data
mass of bullet m= 3g= 0.03kg
initial velocity u = 400m/s
final velocity v= 200 m/s
Step two:
1.The bullet's lost kinetic energy went inside the tree.
2. The energy transferred is computed as
= initial KE- KE final
Initial KE= 1/2mu^2
Initial KE= 1/2*0.03*400^2
Initial KE= 1/2*0.03*160000
Initial KE= 1/2*4800
Initial KE= 2400J
KE final= 1/2mv^2
KE final= 1/2*0.03*200^2
KE final= 1/2*0.03*40000
KE final= 1/2*1200
KE final= 600J
KE transferred = 2400-600
KE transferred= 1800J
