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vivado [14]
3 years ago
14

What is the difference between m/s and m.s.​

Physics
2 answers:
saw5 [17]3 years ago
7 0

Answer:

Hi there. I hope your having an amazing day. Here is the answer to you question. Give me brainlest please!

Explanation:

m/s rate of change of displacement per sec. ie velocity

m/s^2 is (m/s)/s ie rate of change of velocity per sec. ie acceleration plantation

vfiekz [6]3 years ago
5 0

Answer

m/s rate of change of dispalcement per sec. ie velocity

m/s^2 is (m/s)/s ie rate of change of velocity per sec. ie accelerationplanation:

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Find the change in kinetic energy of a 1.0 kg fish leaping to the right at 12.0 m/s.
sp2606 [1]

Answer:

6J

Explanation:

Given parameters:

Mass of fish  = 1kg

Velocity  = 12m/s

Unknown:

Change in kinetic energy = ?

Solution:

Kinetic energy is the energy due to the motion of a body. It is mathematically given as:

       K.E  = \frac{1}{2}  m v²  

Now, insert the parameters and solve;

  K.E  =  \frac{1}{2}  x 1 x 12  = 6J

The change in kinetic energy is 6J

4 0
2 years ago
Read 2 more answers
Determine the binding energy of an F-19 nucleus. The F-19 nucleus has a mass of 18.99840325 amu. A proton has a mass of 1.00728
Anvisha [2.4K]

Answer:

Energy = 1.38*10^13 J/mol

Explanation:

Total number of proton in F-19 = 9

Total number of neutron in F-19 = 10

Expected Mass of F-19  

= 9*1.007 + 10*1.008 = 19.152 u

Actual  mass of F-19 = 18.998 u

Energy of one particle of F-19 = 931.5*Δm = 931.5*(19.152-18.998)

= 143.234 MeV

Energy of one mole of F-19 = 143.234*10^6*1.6*10^-19*6.022*10^23  

= 1.38*10^13 J/mol

8 0
2 years ago
Peak wavelength of light coming from a star with a temp of 4300k
PSYCHO15rus [73]

from Wein's law

\frac{k}{ \lambda_{max} }  = T \\ \lambda_{max} =  \frac{k}{T}  \\ \lambda_{max} =  \frac{3.898 \times  {10}^{ - 3} }{4300}   \\  = 9.065 \times  {10}^{ - 7}

3 0
2 years ago
A lever has an effort arm that is 8 meters long and the resistance arm that is 1.5 meters long, how much effort is needed to lif
ruslelena [56]
We are given with two measurements of the arm and an input weight. To answer this problem,we need to balance the forces and use the lengths of the arms. 
209 N * 8 m = x * 1.5 m
x = 1114.67 N

it takes 1114.67 N to lift the input weight
6 0
3 years ago
Read 2 more answers
A small branch is wedged under a 200 kg rock and rests on a smaller object. The small object that creates a pivot point is calle
KiRa [710]

Answer:

F = 326.7 N

Explanation:

given data

mass m = 200 kg

distance d = 2 m

length L = 12 m

solution

we know force exerted by the weight of the rock that is

W = m × g   ..............1

W = 200 × 9.8

W = 1960 N

and

equilibrium the sum  of the moment about that is

∑Mf = F(cos∅) L - W (cos∅) d  = 0

here ∅ is very small so cos∅ L = L and cos∅ d = D

so F × L - W × d = 0       .................2

put here value

F × 12 - 1960 × 2 = 0

solve it we get

F = 326.7 N

8 0
2 years ago
Read 2 more answers
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