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iris [78.8K]
1 year ago
10

A certain circuit is composed of two series resistors. The total resistance is 10 Ohms. One of the resistors is 4 Ohms. The othe

r resistor value is
a. 6 Ohms
b. 8 Ohms
c. 12 Ohms
d. 14 Ohms
Physics
1 answer:
Mariulka [41]1 year ago
4 0
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

  • A certain circuit is composed of two series resistors
  • The total resistance is 10 ohms
  • One of the resistor is 4 ohms

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • We have to find the value of other resistor?

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

We know that,

In series combination,

  • When a number of resistances are connected in series, the equivalent I.e resultant resistance is equal to the sum of the individual resistances and is greater than any individual resistance

<u>That </u><u>is</u><u>, </u>

Rn in series = R1 + R2 + R3.....So on

<u>Therefore</u><u>, </u>

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

We have,

R1 + R2 = 10 Ω

4 + R2 = 10Ω

R2 = 10 - 4

R2 = 6Ω

Hence, The value of R2 resistor in series is 6Ω

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Answer: The amplitude is 0. (assuming that the amplitude ot both initial waves is the same)

Explanation:

When two monochromatic light waves of the same wavelength and same amplitude undergo destructive interference, means that the peak of one of the waves coincides with the trough of the other, so the waves "cancel" each other in that point in space.

Then if two light waves undergo destructive interference, the amplitude of the resultant wave in that particular point is 0.

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The moon's mass is 7.34x10-kg and it is 3.8x10m away from earth. Calculate the gravitational force of attraction between earth a
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Again I think you did not give the right constants. So I would use the correct constants for mass of moon and distance from earth to moon.

<span>The formula for force of attraction between any two bodies in the universe
F  =  GMm / r^2.      (Newton's Universal law of Gravitation).

G = Universal gravitational constant, G = 6.67 * 10 ^ -11  Nm^2 / kg^2.
M = Mass of Earth. = 5.97 x 10^24 kg.
m = mass of moon = 7.34 x 10^22  kg.
r = distance apart, between centers = in this case it is the distance from Earth to the Moon
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(Sorry I could not assume with the values you gave, they are wrong, and if we use them we would be insulting Physics).


So F = ((6.67 * 10 ^ -11)*(5.97 x 10^24)*(7.34 * 10^22)) / (3.8 x 10^8)^2.
  Punch it all up in your calculator.
 
I used a Casio 991 calculator, it should be one of the best in the world.Really lovely calculator, that has helped me a lot in computations like this. I am thankful for the Calculator.

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Which of the following statements concerning the nuclear force is false? O The nuclear force is attractive and not repulsive. O
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Answer:

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Explanation:

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  • It has the shortest range.
  • Its main function is to hold the subatomic particles together in nature.
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  • At about 1 femtometer the nuclear force is very strongly attractive in nature but at distance greater than 2.5 femtometer it fades away.
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What is the mass of an atom with six protons, seven neutrons, and eight electrons?
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2 years ago
Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a −80-nC charge at x = −4 m on
disa [49]

Answer:

V = 48 Volts

Explanation:

Since we know that electric potential is a scalar quantity

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V = V_1 + V_2 + V_3

here we have potential due to 50 nC placed at y = 6 m

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V_1 = \frac{(9\times 10^9)(50 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_1 = 45 Volts

Now potential due to -80 nC charge placed at x = -4

V_2 = \frac{kQ}{r}

V_2 = \frac{(9\times 10^9)(-80 \times 10^{-9})}{12}

V_2 = -60 Volts

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V_3 = \frac{kQ}{r}

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V_3 = 63 Volts

Now total potential at this point is given as

V = 45 - 60 + 63 = 48 Volts

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3 years ago
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