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Alenkasestr [34]
2 years ago
8

Ellen needs to move a heavy box across the floor and then place it on a shelf that is four feet above the floor. Which use of ma

chines would most likely require the least amount of force in order to get the box on the shelf?
sliding the box up an inclined plane to the shelf
rolling the box up an inclined plane on a cart
sliding the box across the floor and then lifting it using a pulley
rolling the box across the floor in a cart and then using a pulley
Physics
2 answers:
Naily [24]2 years ago
5 0

Option B is correct: Rolling the box up an inclined plane on a cart.

When using the inclined, Ellen needs to overcome frictional force and the weight component of the box along the ramp which will be less than the total weight of the heavy box. Now, in sliding and rolling the weight of the heavy box along the ramp will be same but the difference will come in the type of the frictional force. Since, the rolling friction is less than the sliding friction. Hence, less force will be required when the box is rolled up an inclined plane on a cart.

OleMash [197]2 years ago
3 0

The correct answer is:

B. Rolling the box up an inclined plane on a cart

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Distance covered in 360 s

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2 years ago
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The magnetic field at the center of a 1.40-cm-diameter loop is 2.50 mT . PART A) What is the current in the loop?
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Explanation:

It is given that,

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(A) Magnetic field of a current loop is given by :

B=\dfrac{\mu_oI}{2r}

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I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 2.5\times 10^{-3}\times 0.007}{4\pi \times 10^{-7}}

I = 27.85 A

(B) Magnetic field at a distance r from a wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

r=\dfrac{\mu_o I}{2\pi B}

r=\dfrac{4\pi \times 10^{-7}\times 27.85}{2\pi \times 2.5\times 10^{-3}}

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3 0
3 years ago
A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re
fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

PV=nRT

For a gas

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When the temperature of the gas is increased

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Divided equation (I) by equation (II)

\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}

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P_{2}=\dfrac{10\times368}{2\times286}

P_{2}= 6.433\ atm

P_{2}=6.4\ atm

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

4 0
2 years ago
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