When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of
2 answers:
Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)
Step : Put a 3 in front of CO2 (g) to balance C
=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H
Step 2: Put a 4 in front of H2O
=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)
Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:
=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)
You can verify that the equation is balanced.
So, the answer is that the coefficient in front of O2 is 5.
<span><span>Reaction stoichiometryLimiting reagent</span><span>CompoundCoefficientMolar MassMolesWeight</span><span>C3H8144.09562</span><span>O2531.9988</span><span>CO2344.0095</span><span>H2O4<span>18.01528</span></span></span><span>Balanced equation:
C3H8 + 5 O2 = 3 CO2 + 4 H2O</span>
<span>Reaction type: combustion
</span>
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Hope it helps :)
I think the answer would be nitrogen
a balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.
I’m pretty sure that they mostly design building structures!
O: 1*2 = 2*1
<span>H 2 + 2 = 2*2 </span>
<span>answer C hope you get it right</span>
