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DanielleElmas [232]
3 years ago
15

When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of

Chemistry
2 answers:
Anastaziya [24]3 years ago
7 0
Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)

Step : Put a 3 in front of CO2 (g) to balance C

=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H

Step 2: Put a 4 in front of H2O

=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)

Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:

=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)

You can verify that the equation is balanced.

So, the answer is that the coefficient in front of O2 is 5.
neonofarm [45]3 years ago
6 0

<span><span>Reaction stoichiometryLimiting reagent</span><span>CompoundCoefficientMolar MassMolesWeight</span><span>C3H8144.09562</span><span>O2531.9988</span><span>CO2344.0095</span><span>H2O4<span>18.01528</span></span></span><span>Balanced equation:
C3H8 + 5 O2 = 3 CO2 + 4 H2O</span>
<span>Reaction type: combustion
</span>
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1,2-Dihydronaphthalene is at a lower energy level because of this stabilization.

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C. identify a set of four possible quantum numbers for the circled electron in manganese (mn). (there is more than one correct a
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Although you have not provided the circled electron, I can help you with a wide explanation.

1) Atomic number of manganese is 25. That means that it has 25 protons and 25 electrons.

2) Those 25 electrons are distributed (electron configuration) as per the quantum rules:

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ii) For the 5 electrons in 3d

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