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DanielleElmas [232]
3 years ago
15

When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of

Chemistry
2 answers:
Anastaziya [24]3 years ago
7 0
Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)

Step : Put a 3 in front of CO2 (g) to balance C

=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H

Step 2: Put a 4 in front of H2O

=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)

Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:

=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)

You can verify that the equation is balanced.

So, the answer is that the coefficient in front of O2 is 5.
neonofarm [45]3 years ago
6 0

<span><span>Reaction stoichiometryLimiting reagent</span><span>CompoundCoefficientMolar MassMolesWeight</span><span>C3H8144.09562</span><span>O2531.9988</span><span>CO2344.0095</span><span>H2O4<span>18.01528</span></span></span><span>Balanced equation:
C3H8 + 5 O2 = 3 CO2 + 4 H2O</span>
<span>Reaction type: combustion
</span>
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