Question

When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of

Answer 1

Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)

Step : Put a 3 in front of CO2 (g) to balance C

=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H

Step 2: Put a 4 in front of H2O

=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)

Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:

=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)

You can verify that the equation is balanced.

So, the answer is that the coefficient in front of O2 is 5.

Answer 2

Reaction stoichiometryLimiting reagentCompoundCoefficientMolar MassMolesWeightC3H8144.09562O2531.9988CO2344.0095H2O418.01528Balanced equation:
C3H8 + 5 O2 = 3 CO2 + 4 H2O
Reaction type: combustion