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xeze [42]
3 years ago
14

The starting pressure of a 15°C system was 1.50 atm. If the pressure rose to 1216 torr, what is the new temperature in Celsius?

Chemistry
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

The new temperature is 34.21 °C

Explanation:

Step 1: Data given

Temperature of the system = 15°C

Pressure at 15°C is 1.50 atm

The pressure rose to 1216 torr (=1216/760 = 1.6 atm)

Step 2: Calculate the new temperature

P1/T1 = P2/T2

⇒ with P1 = the initial pressure = 1.50 atm

⇒ with T1 = the initial temperature = 15°C = 288.15 K

⇒ with P2 = the initial pressure = 1.60 atm

⇒ with T2 = the initial temperature = TO BE DETERMINED

T2 = T1 * (P2 / P1)

T2 = 288.15 * (1.60/1.50)

T2 = 307.36 K = 34.21 °C

The new temperature is 34.21 °C

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Answer:-

1) 6 mol

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Explanation: -

Mass of Ozone = 48 g

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Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

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b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
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Answer:

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