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Zanzabum
3 years ago
13

A train travels 77 kilometers in 1 hour, and the 66 kilometers in 1 hour. What is the average speed?

Physics
1 answer:
Kipish [7]3 years ago
6 0

Average speed = (total distance covered) / (time to cover the distance)

Total distance = (77km + 66km) = 143 kilometers

Time to cover the distance = 2 hours

Average speed = (143 km) / (2 hours) =  71.5 km per hour
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How can liquid pressure phenomena be used in daily life. Give one example with explanation of working​?
N76 [4]

Answer:

An example in which liquid pressure phenomena can be used in daily life is in Water blasting

Explanation:

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There are different varieties of water blasting, including;

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8 0
3 years ago
What force could be applied to a box to make the net force in the horizontal direction of zero​
Kazeer [188]

If there is no friction, the force that moves the box forward horizontally must be matched by the same force.

If there is friction, then the force moving it forward = frictional force + the additional force you need to add.

6 0
3 years ago
an athlete swims the distance from one end of a 50m pool to the other end in a time of 25 s what is The Athlete's average speed
vredina [299]

Answer:

2.5 N

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3 0
3 years ago
in a horse cart, each of the two horses pull with a force of 1000N. find the resultant force. give reasons.
sp2606 [1]
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4 0
3 years ago
Approximate the skin friction drag on a 1m long by 60 cm diameter cylinder, located axially in a wind tunnel, when the air speed
TiliK225 [7]

Answer:

The drag force is 1.76\times10^{-2}\ N

Explanation:

Given that,

Diameter = 60 cm

Length = 1 m

Air speed = 4.5 m/s

Temperature = 50°C

We need to calculate the Reynolds number

Using formula of Reynolds number

R_{e}=\dfrac{vl}{\mu}

Put the value into the formula

R_{e}=\dfrac{4.5\times1}{1.900\times10^{-5}}

R_{e}=2.368\times10^{5}

We need to calculate the drag coefficient

Using formula of drag coefficient

C_{d}=\dfrac{2\times0.646}{\sqrt{R_{e}}}

Put the value into the formula

C_{d}=\dfrac{2\times0.646}{\sqrt{2.368\times10^{5}}}

C_{d}=0.002655

We need to calculate the drag force

Using formula of drag force

F_{d}=\dfrac{1}{2}\times C_{d}\times\rho\times A\times v^2

Put the value into the formula

F_{d}=\dfrac{1}{2}\times0.002655\times1.095\times0.6\times1\times(4.5)^2

F_{d}=0.01766\ N

F_{d}=1.76\times10^{-2}\ N

Hence, The drag force is 1.76\times10^{-2}\ N

3 0
3 years ago
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