Answer:
number of Al atom =54÷27=2atom of Al. number of o atom = 160÷16=10 atom of o . =214U MASS of ALO2.
1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4
The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.
Now add all the coefficients/moles.
9 is the sum of all the coefficients.
Answer:
Formic acid, citric acid, Oxalic acid, washing soda, baking soda, etc. can be some examples of natural acids and natural bases. They both have domestic, industrial, and various other purposes.
Explanation:
<h3><u>
NATURAL ACIDS</u>
:</h3>
There are lots of natural acids present in our nature. Some of them are the following:
> <u>Formic acid</u>
USE: It is used in the stimulation of oil and gas wells as it is less reactive towards the metal.
> <u>Citric acid</u>
USE: It is considered as the best rust remover as it doesn't harm the metal just remove the rust.
> <u>Oxalic acid</u>
USE: It easily remove iron and ink stains and that's why it is used as an acid rinsing material in Laundries.
<h3><u>
NATURAL BASES</u>
:</h3>
There is a variety of natural base found in our nature which founds a lot of uses in day to day life. some of them are the following:
> <u>Washing soda</u>
USE: It is used in commercial detergent mixture to treat hard water.
> <u>Baking soda</u>
USE: It is the best rising agent used mostly in cooking and for domestic purposes like removing stains, etc..
Answer:
697 g
Explanation:
Ethanol (C₂H₅OH) and butanoic acid (C₃H₇COOH) react to form ethyl butanoate (C₃H₇COOC₂H₅) and water (H₂O).
C₂H₅OH + C₃H₇COOH → C₃H₇COOC₂H₅ + H₂O
The molar ratio of C₂H₅OH to C₃H₇COOC₂H₅ is 1:1. The moles of C₃H₇COOC₂H₅ produced from 6.00 moles of C₂H₅OH are:
6.00 mol C₂H₅OH × (1 mol C₃H₇COOC₂H₅/1 mol C₂H₅OH) = 6.00 mol C₃H₇COOC₂H₅
The molar mass of C₃H₇COOC₂H₅ is 116.16 g/mol. The mass corresponding to 6.00 mol is:
6.00 mol × (116.16 g/mol) = 697 g
I can't actually answer this one if the empirical formula is not given. Luckily, I've found a similar problem from another website. The problem is shown in the picture attached. It shows that the empirical formula is CH₂O. Let's calculate the molar mass of the empirical formula.
Molar mass of E.F = 12 + 2(1) + 16 = 30 g/mol
Then, let's divide this to the molar mass of the molecular formula.
Molar mass of M.F/Molar mass of E.F = 180/30 = 6
Therefore, let's multiply 6 to each subscript in the empirical formula to determine the actual molecular formula.
<em>Actual molecular formula = C₆H₁₂O₆</em>
