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Ymorist [56]
3 years ago
13

The nucleus of a large atom splits and two smaller atoms are formed. Energy is released in the process. What is the name of this

process?
Physics
2 answers:
Ganezh [65]3 years ago
4 0

That process is called "nuclear fission".

creativ13 [48]3 years ago
4 0

Answer: Nuclear Fission

Explanation:

Nuclear fission reactions are one of the nuclear reactions in which heavier nuclei splits into two or more lighter nuclei. In these reactions, neutrons are released with a large amount of energy.

General equation for nuclear fission reactions is given by:

_Z^A\textrm{X}\rightarrow _{Z-U}^{A-V}\textrm{Y}+_U^V\textrm{W}+3_0^1n+\text{Energy}

Nuclear fusion reactions are one of the nuclear reactions in which two or more lighter nuclei combines to form heavier nuclei. In these reactions,   large amount of energy is released.

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How does hydroelectric energy work
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<span>The water is held behind a dam, forming reservoir. The force of the water being released from the reservoir through the dam spins the blades of a giant turbine.</span>
6 0
3 years ago
1. When you have different masses for each sphere, how does the force that the larger mass sphere exerts on the smaller mass sph
aleksandrvk [35]

1) The forces are equal (Newton's third law of motion)

2) The force between the spheres will quadruple

3) The force of gravity exerted by the notebook on you is negligible

Explanation:

1)

In this part of the problem, we want to compare the gravitational force exerted by the larger mass sphere on the smaller mass sphere to the force exerted by the smaller mass sphere to the larger mass sphere.

We can do this by using Newton's third law of motion, which states that:

<em>"When an object A exerts a force (called </em><em>action</em><em>) on an object B, then object B exerts an equal and opposite force (called </em><em>reaction</em><em>) on object A"</em>

In this problem, we can identify the larger mass sphere as object A and the smaller mass sphere as object B. This law tells us that the two forces are equal in magnitude and opposite in direction: therefore, the gravitational force exerted by the larger mass sphere on the smaller mass sphere is equal to the force exerted by the smaller mass sphere to the larger mass sphere.

2)

The magnitude of the gravitational force between the two spheres is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m_1, m_2 are the masses of the two spheres

r is the separation between the two spheres

In this problem, we are asked to find what happens when the distance between the spheres is halved, therefore when the new distance is

r'=\frac{r}{2}

Substituting into the equation, we find

F'=G\frac{m_1 m_2}{r'^2}=G\frac{m_1 m_2}{(r/2)^2}=4(\frac{Gm_1 m_2}{r^2})=4F

So, the force between the two spheres will quadruple.

3)

We can give an estimate for the gravitational force exerted by your notebook on you.

As we said, the magnitude of the gravitational force is

F=G\frac{m_1 m_2}{r^2}

Where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

Let's estimate the following:

m_1 = 60 kg is your mass

m_2 = 2 kg is the mass of the notebook

r=1 m, assuming the notebook is at 1 metre from you

Substituting,

F=(6.67\cdot 10^{-11})\frac{(60)(2)}{1^2}=8.0\cdot 10^{-9} N

We see that this force has an extremely small value: therefore, it is almost negligible in daily life, where other much stronger forces act on you.

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

8 0
3 years ago
5. Which pair of words, in order, correctly completes
sattari [20]

Answer:

B is an answer.

3 0
3 years ago
Is 0.0 m/s squared increasing or decreasing
Agata [3.3K]
Decrease because its 0.0 m/s
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3 years ago
According to the concept of length contraction, what happens to the length of an object as it approaches the speed of light and
lord [1]
When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion.
The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops.
The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.
8 0
4 years ago
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