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Ymorist [56]
3 years ago
13

The nucleus of a large atom splits and two smaller atoms are formed. Energy is released in the process. What is the name of this

process?
Physics
2 answers:
Ganezh [65]3 years ago
4 0

That process is called "nuclear fission".

creativ13 [48]3 years ago
4 0

Answer: Nuclear Fission

Explanation:

Nuclear fission reactions are one of the nuclear reactions in which heavier nuclei splits into two or more lighter nuclei. In these reactions, neutrons are released with a large amount of energy.

General equation for nuclear fission reactions is given by:

_Z^A\textrm{X}\rightarrow _{Z-U}^{A-V}\textrm{Y}+_U^V\textrm{W}+3_0^1n+\text{Energy}

Nuclear fusion reactions are one of the nuclear reactions in which two or more lighter nuclei combines to form heavier nuclei. In these reactions,   large amount of energy is released.

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At the equator earth rotates with a velocity of about 465 m/s.
Dafna1 [17]
The given velocity is 465 m/s.

Part a.
465 \,  \frac{m}{s} =(465 \times 10^{-3} \,  \frac{km}{s})*( 3600 \,  \frac{s}{h} ) = 1674 \,  \frac{km}{h}
Answer: 1674 km/h

Part b.
1674  \frac{km}{h} = (1674 \,  \frac{km}{h})*(24 \,  \frac{h}{day}  ) = 40176 \,  \frac{km}{day}
Answer: 40,176 km/day.

 
3 0
3 years ago
Read 2 more answers
The earth and the moon exert forces on each other which forces is greater? explain
Helen [10]

Thank you for your question, what you say is true, the gravitational force exerted by the Earth on the Moon has to be equal to the centripetal force.

An interesting application of this principle is that it allows you to determine a relation between the period of an orbit and its size. Let us assume for simplicity the Moon's orbit as circular (it is not, but this is a good approximation for our purposes).

The gravitational acceleration that the Moon experience due to the gravitational attraction from the Earth is given by:

ag=G(MEarth+MMoon)/r2

Where G is the gravitational constant, M stands for mass, and r is the radius of the orbit. The centripetal acceleration is given by:

acentr=(4 pi2 r)/T2

Where T is the period. Since the two accelerations have to be equal, we obtain:

(4 pi2 r) /T2=G(MEarth+MMoon)/r2

Which implies:

r3/T2=G(MEarth+MMoon)/4 pi2=const.

This is the so-called third Kepler law, that states that the cube of the radius of the orbit is proportional to the square of the period.

This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.


8 0
3 years ago
If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will
densk [106]

Answer:

The voltage will quadruple

Explanation:

The power dissipated in a circuit is given by

P=\frac{V^2}{R}

where

V is the voltage

R is the resistance

In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

P'=\frac{V'^2}{R}=\frac{(2V)^2}{R}=4\frac{V^2}{R}=4 P

so, the power dissipated will quadruple.

6 0
3 years ago
When you are ice skating, to get started, you push your stake backwards on the ice and, as a result, begin to move forward. whic
LUCKY_DIMON [66]

C. Newtons third law of motion

Because eventually, the frictional forces will slow you to a halt. Newton's Third Law of Motion For every action there is an equal and opposite reaction. When they push off against the ice, or "stroke" with their skates, they are applying a force down and back against the ground.

Hope this helps!

8 0
3 years ago
When you throw a ball upward, its kinetic energy and its potential energy . When the ball reaches maximum height, its kinetic en
emmasim [6.3K]
It has zero kinetic energy, more potential energy
8 0
3 years ago
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