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Ymorist [56]
3 years ago
13

The nucleus of a large atom splits and two smaller atoms are formed. Energy is released in the process. What is the name of this

process?
Physics
2 answers:
Ganezh [65]3 years ago
4 0

That process is called "nuclear fission".

creativ13 [48]3 years ago
4 0

Answer: Nuclear Fission

Explanation:

Nuclear fission reactions are one of the nuclear reactions in which heavier nuclei splits into two or more lighter nuclei. In these reactions, neutrons are released with a large amount of energy.

General equation for nuclear fission reactions is given by:

_Z^A\textrm{X}\rightarrow _{Z-U}^{A-V}\textrm{Y}+_U^V\textrm{W}+3_0^1n+\text{Energy}

Nuclear fusion reactions are one of the nuclear reactions in which two or more lighter nuclei combines to form heavier nuclei. In these reactions,   large amount of energy is released.

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Two particles with positive charges q1 and q2 are separated by a distance s. Part A Along the line connecting the two charges, a
liraira [26]

Answer:

x=s*\frac{q_{1} +-\sqrt{q_{1}q_{2}}}{q_{1}-q_{2}}

we choose the sign, in order to x<s

Explanation:

x=distance from q1

E_{1} =E_{2}

k*q_{1}/x^{2}=k*q_{2}/(s-x)^2}

q_{1}*(s^{2}-2sx+x^{2})-q_{2}x^{2}=0

(q_{1}-q_{2})x^{2}-2sq_{1}x+q_{1}*s^{2}=0

this is a quadratic equation:

x=\frac{-b+-\sqrt{b^{2}-4ac} }{2a}=\frac{2sq_{1} +-\sqrt{(-2sq_{1})^{2}-4(q_{1}-q_{2})q_{1}s^{2}}} {2(q_{1}-q_{2})}

x=s*\frac{q_{1} +-\sqrt{q_{1}q_{2}}}{q_{1}-q_{2}}

4 0
4 years ago
What is the angle between the incident ray and the normal ray called?
alisha [4.7K]

Answer:

A, the angle of refraction

8 0
4 years ago
Read 2 more answers
The current in a resistor is 2.0 A, and its power is 78 W. What is the voltage?
bazaltina [42]

Answer:

39 volts

Explanation:

Use the equation P=VI

78=V(2)

V=39

6 0
3 years ago
Vector B has x, y, and z components 4, 6, and 3, respectively.
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Bbbbbbbbbbbbbb gygffdd
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3 years ago
A centrifugal pump is operating at a flow rate of 1 m3/s and a head of 20 m. If the specific weight of water is 9800 N/m3 and th
tamaranim1 [39]

Answer:

<em>The power required by the pump is nearly 230.588 kW</em>

Explanation:

Flow rate of the pump Q = 1 m^3/s

the head flow H = 20 m

specific weight of water γ = 9800 N/m^3

efficiency of the pump η = 85%

First note that specific gravity of water is the product of the density of water and acceleration due to gravity.

γ = ρg

where ρ is density. For water its value is 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

The power to lift this water at this rate will be gotten from the equation

P = ρgQH

but ρg = γ

therefore,

P = γQH

imputing values, we'll have

P = 9800 x 1 x 20 = 196000 W

But the centrifugal pump that will be used will only be able to lift this amount of water after the efficiency factor has been considered. The power of pump needed must be greater than this power.

we can say that

196000 W is 85% of the power of the pump power needed, therefore

196000 = 85% of P_{p}

where P_{p} is the power of the pump needed

85% = 0.85

196000 = 0.85P_{p}

P_{p} = 196000/0.85 = 230588.24 W

<em>Pump power = 230.588 kW</em>

3 0
3 years ago
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