Question

Arrange the liquids pentane (CH3CH2CH2CH2CH3), pentanol (CH3CH2CH2CH2CH2OH), and pentanal (CH3CH2CH2CH2CHO) in order of decreasing viscosity, surface tension, and boiling point. Rank from highest to lowest viscosity, surface tension, and boiling point. To rank items as equivalent, overlap them.

Answer 1

Answer:

According to decreasing viscosity = pentanol > pentanal > pentane.

surface tension =  pentanol > pentanal > pentane.

Boiling point = pentanol > pentanal > pentane.

Explanation:

pentane (CH3CH2CH2CH2CH3), pentanol (CH3CH2CH2CH2CH2OH), and pentanal (CH3CH2CH2CH2CHO) in order of decreasing viscosity, surface tension, and boiling point. They all have same sequence in which they are in order hydrogen bonding > dipole dipole interactions > van der waals dispersion forces.

Surface tension is the property of  liquid's surface that resist the force and caused by the unbalance forces. Viscosity is related to  liquid's  resistance to being moved. This is caused by the friction between molecules and Branching decreasing the boiling point.

Answer 2

Answer:

Explanation:

These properties are governed by intermolecular forces. The most important part here is the oxygen interaction with the surroundings. For temperature the decreasing order is pentanol, pentanal and pentane. For viscocity: pentanol, pentanal and pentane. For surface tension: pentanol, pentanal and pentane.

This order, as said before, is due to the interaction of oxygen with the surroundings, within the intermolecular forces we can find van der waals forces and hydrogen bonds, it is also know that H-bonds are stronger than van der waals forces so then that is why we have this type of interactions.