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Tanya [424]
2 years ago
6

Answer this ASAP please!! Question: How many magnesium atoms does magnesium oxide need? (Science) (ONLY ANSWER IF YOU KNOW WHAT

IT IS)

Chemistry
1 answer:
aliina [53]2 years ago
7 0

Answer:

40.3 for the unit that represents the minimum amount of magnesium oxide I beilieve.

Explanation:

Magnesium atoms are heavier than oxygen atoms, so we expect more than 50% of magnesium in the weight composition. Taking just one atom of Mg and one atom of O you will get a mass of 16.0 + 24.3 = 40.3.

Hope this helps! Please tell me if you have any questions :))

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Match the image with the correct invention
PolarNik [594]

Answer:

1. Watt stream engine

2. McCormick reaper

3. Fulton steamboat

These are the correct answers.

Have A good day!!  :)

8 0
3 years ago
Read 2 more answers
Which reaction type is the following: AgF + CaCl2 --> AgCl + CaF2
nevsk [136]

Explanation:

{\small{\underline{\bf{\red{answer...}}}}} \\  \\

\small\mathfrak\purple{Double  \: displacement \:  reaction} \\  \\ \small\mathfrak\orange{hope \: it \: helps...}

6 0
2 years ago
When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr
konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

4 0
3 years ago
Why cant (NaCl) light the bulb until the NaCl is dissolved in water. *
Aneli [31]

Answer:

NaCl will only conduct electricity in solutions

Explanation:

For electrical conduction, free mobile electrons as seen in most metals must be present or ions which are charged particles must be available for solutions and molten substances.

  • Sodium chloride is an ionic compound without free mobile electrons or ions despite being ionic.
  • It will maintain a subtle and unique charge stability when in solid form.
  • In solid, the ions are not free to move and remain locked up in the solid mass.
  • When introduced into a solution, the ions becomes free to move and this will aid electrical conduction.
6 0
3 years ago
Red light has a wavelength of about 6.5 x 10-7m. Find its frequency. Show all work.
ozzi
For this problem we use the wave equation. It is expressed as the speed (c) is equal to the product of frequency (f) and wavelength (v).

c = v x f

We know the wavelength of the an red light which is 6.5 x 10^-7 m. Now, we solve for the wavelength of the unknown wave to see the relation between the two waves.

2.998 X 10^8 = 5.3 X 10^15 X v
v = 2.998 X 10^8 / (5.3 X 10^15) = 5.657 X 10^-8 m

Therefore, the wavelength of the unknown wave is less than the wavelength of the red light.
3 0
3 years ago
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