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omeli [17]
3 years ago
11

Is this right ? if it’s wrong correct me

Chemistry
2 answers:
Dimas [21]3 years ago
4 0
You can go to a website about that it will give you the answers
Shalnov [3]3 years ago
4 0
A website will be able to check your answers for you when doing periodic tables.
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C3H8 + 5O2 → 3CO2+ 4H2O, if 5.75L of oxygen are consumed in the above reaction, how many L of carbon dioxide are produced?
anzhelika [568]

Answer: 3.45 L carbon dioxide are produced

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{5.75L}{22.4L}=0.257moles

C_3H_8+5O_2(g)\rightarrow 3CO_2+4H_2O  

According to stoichiometry :

5 moles of O_2 produce =  3 moles of CO_2

Thus 0.257 moles of O_2 will produce=\frac{3}{5}\times 0.257=0.154moles  of CO_2  

Volume of CO_2=moles\times {\text {Molar volume}}=0.154moles\times 22.4L/mol=3.45

Thus 3.45 L carbon dioxide are produced

6 0
3 years ago
Take the following out of scientific notation 3.74 x 10^7<br> Please help me
erastovalidia [21]

Answer:

37400000000 is the <em>ans</em>

5 0
3 years ago
8. Which of the following is TRUE about limiting and excess reactants?
Ivahew [28]
B. The limiting reactant determines the max amount of product that can be formed
5 0
3 years ago
Las sustancias ionicas y los metale sson electricamente neutros. ¿como es esto posible si estan formados por iones, que posen ca
Anton [14]

Answer:

ver explicacion

Explanation:

Los iones se forman cuando las especies químicas pierden o ganan electrones.

Las sustancias iónicas consisten en un ión positivo y negativo cuyas cargas se equilibran exactamente entre sí, por lo que el compuesto iónico es neutro.

Los átomos de metal se mantienen unidos por el enlace metálico. Esto implica la interacción entre iones metálicos cargados positivamente y un mar de electrones negativos. Las cargas positivas de los iones metálicos están exactamente equilibradas por el mar de electrones cargados negativamente, por lo que el metal es neutro.

8 0
3 years ago
51. The radius of gold is 144 pm and the density is 19.32 g/cm3. Does elemental gold have a face-centered cubic structure or a b
Serjik [45]

Answer:

Elemental gold to have a Face-centered cubic structure.

Explanation:

From the information given:

Radius of gold = 144 pm

Its density = 19.32 g/cm³

Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:

a = \sqrt{8} r

a = \sqrt{8} \times 144 pm

a = 407 pm

In a unit cell, Volume (V) = a³

V = (407 pm)³

V = 6.74 × 10⁷ pm³

V = 6.74 × 10⁻²³ cm³

Recall that:

Net no. of an atom in an FCC unit cell = 4

Thus;

density = \dfrac{mass}{volume}

density = \dfrac{ 4 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{6.74 \times 10^{-23} \ cm^3}

density d = 19.41 g/cm³

Similarly; For a  body-centered cubic structure

r = \dfrac{\sqrt{3}}{4}a

where;

r = 144

144 = \dfrac{\sqrt{3}}{4}a

a = \dfrac{144 \times 4}{\sqrt{3}}

a = 332.56 pm

In a unit cell, Volume V = a³

V = (332.56 pm)³

V = 3.68 × 10⁷ pm³

V  3.68 × 10⁻²³   cm³

Recall that:

Net no. of atoms in BCC cell = 2

∴

density = \dfrac{mass}{volume}

density = \dfrac{ 2 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{3.68 \times 10^{-23} \ cm^3}

density =17.78 g/cm³

From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.

This makes the elemental gold to have a Face-centered cubic structure.

3 0
3 years ago
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