How many moles are in 2.23 X 10^50 molecules of H2?

An ionic bond is formed between a metal and a non-metal. Non-metals(-ve ion) are "stronger" than the metal(+ve ion) and can get electrons very easily from the metal. These two opposite ions attract each other and form the ionic bond.

5 0

3 years ago

A certain flexible weather balloon contains 7.4 L of helium gas. Initially, the balloon is in WP at 8500ft, where the temperatur

Free_Kalibri [48]

<h2>The new volume of the balloon at the top of Pikes Peak is 10.2 L</h2>

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 577.0 torr

$P_2$ = final pressure of gas = 400 torr

$V_1$ = initial volume of gas = 7.4 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $20.6^oC=273+20.6=293.6K$

$T_2$ = final temperature of gas = $7.5^oC=273+7.5=280.5K$

Now put all the given values in the above equation, we get:

$\frac{577.0\times 7.4}{293.6K}=\frac{400.0\times V_2}{280.5K}$

$V_2=10.2L$

Thus the new volume of the balloon at the top of Pikes Peak is 10.2 L

Learn more about combined gas law

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3 0

2 years ago

How many moles of Al would be produced from 20 moles of Al2O3? 2Al2O3 -> 4A1 + 302

Evgesh-ka [11]

<h3>Answer:</h3>

$\displaystyle 40 \ mol \ Al$

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

Step 2: Identify Conversions

[RxN] 2 mol Al₂O₃ → 4 mol Al

Step 3: Stoich

[DA] Set up: $\displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 40 \ mol \ Al$

Step 4:Check

Follow sig fig rules and round. We are given 1 sig fig.

Since our final answer already has 1 sig fig, there is no need to round.

4 0

2 years ago