1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kvv77 [185]
3 years ago
15

When a fisher casts his line into the water, the location where he sees the fish is not actually where the fish is, due to refra

ction light. given that the index of refraction is higher in water than in air, is the fish actually farther from the fisher or closer compared to where he sees it?
Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0
The fish is actually farther from you then you think
You might be interested in
What is the change in entropy per mole associated with the melting of gold? the melting point of gold is 1337k and the â†hfus is
riadik2000 [5.3K]
The entropy change<span> of the surroundings is driven by heat flow and the heat flow determines the sign of ΔS</span>surr<span>. It can be calculated by the following expression:

</span>ΔSsurr = -(ΔH) / T

We calculate as follows:

ΔSsurr = -13200 / 1337 = 9.87 J/ K mol

Hope this answers the question. Have a nice day.
6 0
3 years ago
A 620 kg car is traveling at 24 m/s on horizontal ground when it starts up a 30 m high hill. The engine can produce up to 144,00
sweet-ann [11.9K]

Answer:

The kinetic energy of the car at the top of the hill is 140280 Joules.

Explanation:

Mass of the car, m = 620 kg

Speed of the car, v = 24 m/s

Height of the hill, h = 30 m

The engine can produce up to 144,000 J of work during that time, W = 144,000 J

We need to find the kinetic energy of the car at the top of the hill. It can be calculated using conservation of mechanical energy as :

(mgh+K)-\dfrac{1}{2}mv^2=144000

(620\times 9.8\times 30+K)-\dfrac{1}{2}\times 620\times (24)^2=144000

620\times9.8\times30+K=322560

K=140280\ J

So, the kinetic energy of the car at the top of the hill is 140280 Joules. Hence, this is the required solution.

7 0
4 years ago
Please help meeeee!!! ​
prohojiy [21]

Answer:

1. Test tube

2. tongs

3.

4.  FUNNEL

5.  

6.

7. Flask

8. Beaker

9. Bunsen burner

10. Erlenmeyer Flask

11.  Molar and pestle

12. Wire gauze

13.  Graduated cylinder

14. Test tube rack

15.  Pipet

16. Filo

Explanation:

8 0
3 years ago
Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average densit
Ber [7]

Solution :

Acceleration due to gravity of the earth, g $=\frac{GM}{R^2}$

$g=\frac{G(4/3 \pi R^2 \rho)}{R^2}=G(4/3 \pi R \rho)$

Acceleration due to gravity at 1000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-1000) \times 5.5 \times 10^3\right)$

  $= 822486 \times 10^{-8}$

  $=0.822 \times 10^{-2} \ km/s$

 = 8.23 m/s

Acceleration due to gravity at 2000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$

  $= 673552 \times 10^{-8}$

  $=0.673 \times 10^{-2} \ km/s$

 = 6.73 m/s

Acceleration due to gravity at 3000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$

  $= 3371 \times 153.86 \times 10^{-8}$

  = 5.18 m/s

Acceleration due to gravity at 4000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$

  $= 153.84 \times 2371 \times 10^{-8}$

  $=0.364 \times 10^{-2} \ km/s$

 = 3.64 m/s

       

3 0
3 years ago
A hiker travels 300 m [N], turns around and hikes 550 m[S], and then finds out he has to hike back another 50.0 m
bulgar [2K]

Answer:

900 m

Explanation:

Given that,

A hiker travels 300 m [N], turns around and hikes 550 m[S], and then finds out he has to hike back another 50.0 m  [N].

We need to find the total distance travelled by the hiker.

Let north be positive and south be negative direction.

Distance = total path covered

D = 300 + 550 + 50

D = 900 m

So, the required distance is equal to 900 m.

4 0
3 years ago
Other questions:
  • How can astronomers infer approximately how long the universe has been expanding?
    5·2 answers
  • A crane uses a block and tackle to lift a 2200N flagstone to a height of 25m
    15·1 answer
  • Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. How long will the bal
    12·2 answers
  • An older-model car accelerates from 0 to speed v in a time interval of Δt. A newer, more powerful sports car accelerates from 0
    11·1 answer
  • Describe, using the relevant physics, how moving a magnet near a [ 1 2 ] solenoid induces a voltage across it. How does the spee
    6·1 answer
  • A student is creating a table with properties of electromagnetic and mechanical waves.
    11·1 answer
  • Pls pls help me out AHH, what is not true about MEIOSIS?
    7·1 answer
  • WILL MARK BRAINLIEST ONCE I KNOW THE RIGHT ANSWER *(AFTER THE FULL TEST)*
    12·1 answer
  • A solid metal sphere of radius 3 m carries a total charge of -5.5 uc. What is the magnitude of the
    13·1 answer
  • Demarcus launches a small weight into the air. The weight takes 6.4 seconds to reach the ground again. At what time did the weig
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!