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2 years ago

Please help meeeee!!!

Physics

1 answer:

prohojiy [21]2 years ago

8 0

Answer:

1. Test tube

2. tongs

4. FUNNEL

7. Flask

8. Beaker

9. Bunsen burner

10. Erlenmeyer Flask

11. Molar and pestle

12. Wire gauze

13. Graduated cylinder

14. Test tube rack

15. Pipet

16. Filo

Explanation:

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why is it important for scientist and engineer who plan uncrewed missions to accurately know the masses and the paths of the pla

vodka [1.7K]

Answer:

u may find your answer from this link-

https://www.nasa.gov/50th/50th_magazine/scientists.html

Explanation:

8 0

2 years ago

The chemical formula for Glucose is C12H6012.<br> True<br> False

frozen [14]

Answer:

The chemical formula for Glucose is C6H12O6.

<h2>Therefore, The answer would be False.</h2>

Explanation:

7 0

2 years ago

Read 2 more answers

A 75-g mass sits 75 cm from the center of a rotating platform undergoing a uniform angular acceleration of 0.125 rad/s^2. The co

jasenka [17]

Answer:

velocity of mass when it slides of will be 1.36 m/sec

So option (b) will be correct option.

Explanation:

We have given mass of the slits m = 75 gram = 0.075 kg

Radius r = 75 cm = 0.75 m

Coefficient of kinetic friction $\mu =0.250$

Acceleration due to gravity $g=9.8m/sec^2$

When the mass slides of

$\frac{mv^2}{r}=\mu mg$

$v=\sqrt{\mu rg}=\sqrt{0.250\times 0.75\times 9.8}=1.36m/sec$

So velocity of mass when it slides of will be 1.36 m/sec

So option (b) will be correct option.

3 0

3 years ago

Answer this plzzzzzzzzzzzzz

Arlecino [84]

67 is the answer . jen did

5 0

3 years ago

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 92.6 cm and diameter 2.95 cm fr

slavikrds [6]

Answer:

48.4293354946 N

Yes

Explanation:

d = Diameter of rod = 2.95 cm

h = Length of rod = 92.6 cm

$\rho$ = Density of rod = 7800 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Volume of rod

$V=\dfrac{1}{4}\pi d^2h\\\Rightarrow V=\dfrac{1}{4}\times \pi\times (2.95\times 10^{-2})^2\times 92.6\times 10^{-2}$

Mass is given by

$m=\rho V\\\Rightarrow m=7800\times \dfrac{1}{4}\times \pi\times (2.95\times 10^{-2})^2\times 92.6\times 10^{-2}\\\Rightarrow m=4.93673144695\ kg$

Weight is given by

$W=mg\\\Rightarrow W=4.93673144695\times 9.81\\\Rightarrow W=48.4293354946\ N$

The weight of the rod is 48.4293354946 N

The mass of the rod is 4.93673144695 kg which is light. So, I will be able to carry the rod without a cart.

7 0

2 years ago

Please help meeeee!!! ​

Please help meeeee!!!