Answer:
5.3 m/s
Explanation:
First, find the time it takes for him to fall 7m.
y = y₀ + v₀ t + ½ at²
0 = 7 + (0) t + ½ (-9.8) t²
0 = 7 − 4.9 t²
t ≈ 1.20 s
Now find the velocity he needs to travel 6.3m in that time.
x = x₀ + v₀ t + ½ at²
6.3 = 0 + v₀ (1.20) + ½ (0) (1.20)²
v₀ ≈ 5.27 m/s
Rounded to two significant figures, the man must run with a speed of 5.3 m/s.
Valence electrons are the electrons in the outermost energy level of an atom — in the energy level that is farthest away from the nucleus.
I think it's A.
Answer:
Wavelength, ![\lambda=1.28\times 10^{-14}\ m](https://tex.z-dn.net/?f=%5Clambda%3D1.28%5Ctimes%2010%5E%7B-14%7D%5C%20m)
Explanation:
Given that,
Mass of the particle, ![m=4.3\times 10^{-28}\ kg](https://tex.z-dn.net/?f=m%3D4.3%5Ctimes%2010%5E%7B-28%7D%5C%20kg)
Acceleration of the particle, ![a=2.4\times 10^7\ m/s^2](https://tex.z-dn.net/?f=a%3D2.4%5Ctimes%2010%5E7%5C%20m%2Fs%5E2)
Time, t = 5 s
It starts from rest, u = 0
The De Broglie wavelength is given by :
![\lambda=\dfrac{h}{mv}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bh%7D%7Bmv%7D)
v = a × t
![\lambda=\dfrac{h}{mat}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bh%7D%7Bmat%7D)
![\lambda=\dfrac{6.67\times 10^{-34}}{4.3\times 10^{-28}\times 2.4\times 10^7\times 5}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-34%7D%7D%7B4.3%5Ctimes%2010%5E%7B-28%7D%5Ctimes%202.4%5Ctimes%2010%5E7%5Ctimes%205%7D)
![\lambda=1.28\times 10^{-14}\ m](https://tex.z-dn.net/?f=%5Clambda%3D1.28%5Ctimes%2010%5E%7B-14%7D%5C%20m)
Hence, this is the required solution.
Answer:
-67,500 kgm/s
Explanation:
1300 * 20 + 1100 * (-85) = -67,500 kgm/s
Answer:
The frequency increases by a factor of 3.
Explanation:
The relation between speed, wavelength and frequency of a wave is given by :
![v=f\lambda](https://tex.z-dn.net/?f=v%3Df%5Clambda)
or
![f\propto \dfrac{1}{\lambda}](https://tex.z-dn.net/?f=f%5Cpropto%20%5Cdfrac%7B1%7D%7B%5Clambda%7D)
A wave travels at a constant speed. If the wavelength is reduced by a factor of 3, it would mean that the frequency increases by a factor of 3 because there is an inverse relationship between wavelength and frequency.