Which formula describes Boyle's law?

A jetliner flies at a constant speed covering 467 miles in 3.3 hours. What is the speed of the plane in miles per hour?

stellarik [79]

Answer:

141.152 miles per hour is the speed of the plane in miles per hour

Explanation:

Speed of plane = Total distance travelled/total time taken -

v = D/t

Substituting the given values in the above equation, we get

v = 467/3.3 miles /hour

v = 141.152 miles per hour

141.152 miles per hour is the speed of the plane in miles per hour

8 0

3 years ago

Water flows into a horizontal, cylindrical pipe at 1.4 m/s. the pipe then narrows until its diameter is halved. what is the pres

inna [77]

According to the Bernoulli's equation,the pressure difference between the wide and narrow ends of the pipe is given by

$\Delta P= \frac{1}{2} \rho ( v^2_{2} - v^2_{1} )$

Here, $v_{1}$ is the velocity of water through wide ends of cylindrical pipe and $v_{2}$ is the velocity of water through narrow ends of cylindrical pipe.

Given, $v_{1} =1.4 m/s$

Now from equation continuity,

$v_{1} A_{1} = v_{2} A_{2}$ .

Here, $A_{1}$ and $A_{2}$ are cross- sectional areas of wide and narrow ends of cylindrical pipe.

As pipe is circular, so

$v_{1} \pi r^2_{1} = v_{2} \pi r^2_{2}$ .

At the second point, the diameter is halved, which means the radius is also halved. Therefore,

$v_{1} r^2_{1} = v_{2}(\frac{1}{2} r_{1})^2 \\\\ v_{2} = 4 v_{1}$

$v_{2} = 4 \times 1.4 = 5.6 m/s$

Substituting these values with the density of water is $1000 \ kg/m^3$ in pressure difference formula we get.

$\Delta P= \frac{1}{2} \rho ( v^2_{2} - v^2_{1} )=\frac{1}{2}\times 1000 kg/m^3(5.6^2-1.4^2)\\\\ \Delta P = 14700\ Pa$

3 0

3 years ago

Read 2 more answers

You're in a car that gets 37 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and

Sergeu [11.5K]

Answer:

Required diameter of hose pipe = 0.2864 mm

Solution:

From the continuity eqn, the fluid flow rate is given by:

Av = $\frac{V}{t}$

where

A = cross-sectional area = $\pi r^{2}$

r = hose pipe radius

v = velocity of gas

Also, $v = \frac{displacement, d}{time, t}$

Using:

1 gallon = 3.854 l

1 mile = 1609.34 m

$1 m^{3} = 1000 l$

Therefore,

$A\frac{d}{t} = \frac{V}{t}$

$\pi r^{2} = \frac{V}{d}$

$\pi r^{2} = \frac{(1 gal).(\frac{3.7854 l}{gal}).(\frac{10^{- 3} m^{3}}{l})}{37 miles(\frac{1609.34 m}{miles})}$

$6.357\times 10^{- 8} = \pi r^{2}$

$r^{2} = 2.024\times 10^{- 8}$

$r = 1.423\times 10^{- 4} m = 0.1423 mm$

The diameter of the hose pipe = 2r = $2\times 1.423\times 10^{- 4}$

The diameter of the hose pipe = $2.846\times 10^{- 4} m = 0.2846 mm$

4 0

3 years ago

Heat engines convert which type of energy into mechanical work

KonstantinChe [14]

Answer: Heat engines convert chemical energy to mechanical energy

Explanation:

7 0

3 years ago

Một vật nhỏ khối lượng m = 200g được treo vào một lò xo khối lượng không đáng kể, độ cứng k = 80N/m. Kích thích để con lắc dao đ

Alexandra [31]

Explanation:

what is this language? ..............

6 0

2 years ago