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Sidana [21]
3 years ago
7

An 8 Newton wooden block slides across a horizontal wooden floor at constant velocity. What is the magi notice of the force of k

inetic friction between the block and the floor
Physics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

The force of kinetic friction between the block and the floor is 2.4 N

Explanation:

The given parameters are;

The weight of the block = 8 Newtons

The velocity of the block = Constant velocity

Taking the kinetic friction for wood, \mu _k = 0.3, we have;

The normal reaction of the block on horizontal ground, N = The weight of the block = 8 N

The force of kinetic friction between , F_k = \mu _k × N

Therefore, we have;

The force of kinetic friction between the block and the floor, F_k = 0.3 × 8 N = 2.4 N.

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23. If a jogger runs 100 meters west and then turns around and runs 30 meters east. What
marshall27 [118]

Answer:

A

Explanation:

if he goes to the west, the east is opposite so 100-30

7 0
2 years ago
Read 2 more answers
A small dog is trained to jump straight up a distance of 1.2 m. How much kinetic energy does the 7.2-kg dog need to jump this hi
LUCKY_DIMON [66]
Answer:84.672 joules.

Explanation:

1) Data:

m = 7.2 kg
h = 1.2 m
g = 9.8 m / s²

2) Physical principle

Using the law of mechanical energy conservation principle, you have that the kinetic energy of the dog, when it jumps, must be equal to the final gravitational potential energy.

3) Calculations:

The gravitational potential energy, PE, is equal to m × g × h

So, PE = m × g × h = 7.2 kg × 9.8 m/s² × 1.2 m = 84.672 joules.

And that is the kinetic energy that the dog needs.
8 0
3 years ago
If the amplitude of a simple harmonic oscillator is doubled, by what factor does the total energy increase?
dybincka [34]

Answer:

c)by a factor of four

Explanation:

The total energy of a simple harmonic oscillator is given by

E=\frac{1}{2}kA^2

where

k is the spring constant of the oscillator

A is the amplitude of the motion

In this problem, the amplitude of the oscillator is doubled, so

A' = 2A

Therefore, the new total energy is

E'=\frac{1}{2}k(2A)^2=4(\frac{1}{2}kA^2)=4E

So, the total energy increases by a factor 4.

6 0
2 years ago
Dinosaurs’ skeletons can be distinguished from those of other reptiles by the structure of the hips and legs.
jeyben [28]
True, they had a hole in their hip socket that allowed them to run faster than other reptiles of their size at the time. As well as most reptiles besides reptiles had legs to the side, rather than under them like dinosaurs did.

Hope this helps!
5 0
3 years ago
Describe two experiments to determine the speed of propagation of a transverse wave on a rope. You have the following tools to u
AnnZ [28]

Answer:

#See solution for details.

Explanation:

1.

Tools:stopwatch, \ meter \ stick, \ mass \ measuring \ scale , \ force \ measuring  \ device.

Experiment \ 1:Calculate the speed of the wave using the time,t it takes to travel along the rope. Rope's length,L is measured using the meter stick.

-Attach one end of rope to a wall or post, shake from the unfixed end to generate a pulse. Measure the the time it takes for the pulse to reach the wall once it starts traveling using the stopwatch.

-Speed of the pulse can then be obtained as:

v=\frac{L}{t}

Experiment \ 2: Apply force of known value to the rope then use the following relation equation to find the speed of a pulse that travels on the rope.

v=\sqrt{\frac{F}{\mu}}\ ,\mu=\frac{m}{L}

-Use the measuring stick and measuring scale to determine L,m values of the rope then obtain \mu.

-Use the force measuring constant to determine F. These values can the be substituted in Experiment \ 1 to obtain v.

4 0
2 years ago
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