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Sidana [21]
3 years ago
7

An 8 Newton wooden block slides across a horizontal wooden floor at constant velocity. What is the magi notice of the force of k

inetic friction between the block and the floor
Physics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

The force of kinetic friction between the block and the floor is 2.4 N

Explanation:

The given parameters are;

The weight of the block = 8 Newtons

The velocity of the block = Constant velocity

Taking the kinetic friction for wood, \mu _k = 0.3, we have;

The normal reaction of the block on horizontal ground, N = The weight of the block = 8 N

The force of kinetic friction between , F_k = \mu _k × N

Therefore, we have;

The force of kinetic friction between the block and the floor, F_k = 0.3 × 8 N = 2.4 N.

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Which of the following ranching practices contributes to soil erosion?
Natasha2012 [34]

A. overgrazing of livestock

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6 0
3 years ago
An electron is accelerated by a 3.6 kv potential difference. the charge on an electron is 1.60218 × 10−19 c and its mass is 9.10
katen-ka-za [31]
By definition, the potential energy is:
 U = qV
 Where,
 q: load
 V: voltage.
 Then, the kinetic energy is:
 K = mv ^ 2/2
 Where,
 m: mass
 v: speed.
 As the power energy is converted into kinetic energy, we have then:
 U = K
 Equating equations:
 qV = mv ^ 2/2
 From here, we clear the speed:
 v = root (2qV / m)
 Substituting values we have:
 v = root ((2 * (1.60218 × 10 ^ -19) * 3600) /9.10939×10^-31))
 v = 3.56 × 10 ^ 7 m / s
 Then, the centripetal force is:
 Fc = Fm
 mv ^ 2 / r = qvB
 By clearing the magnetic field we have:
 B = mv / qr
 Substituting values:
 B = (9.10939 × 10 ^ -31) * (3.56 × 10 ^ 7) / (1.60218 × 10 ^ -19) * 0.059
 B = 3.43 × 10 ^ -3 T
 Answer:
 
A magnetic field that must be experienced by the electron is:
 
B = 3.43 × 10 ^ -3 T
6 0
3 years ago
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