The answer is 138.75 kgm/s
Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
It is given:
m = 0.25
F = 18,500 N = 18,500 kgm/s²
Δt = 0.0075 s
I = ?
I = F · Δt = 18,500 5kgm/s² * 0.0075 s = 18,500 * 0.0075 kgm/s² * s = 138.75 kgm/s
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Complete Question
A voltaic cell is constructed with two 
electrodes. The two cell compartment have
and
respectively.
What is the cell emf for the concentrations given? Express your answer using two significant figures
Answer:
The value is 
Explanation:
Generally from the question we are told that
The concentration of
at the cathode is
The concentration of
at the anode is
Generally the the cell emf for the concentration is mathematically represented as
![E = E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}](https://tex.z-dn.net/?f=E%20%3D%20%20E%5Eo%20-%20%5Cfrac%7B0.0591%7D%7B2%7D%20log%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5Da%7D%7B%20%5BZn%5E%7B2%2B%7D%5Dc%7D)
Generally the
is the standard emf of a cell, the value is 0 V
So
![E = 0 - \frac{0.0591}{2} * log[\frac{ 2.00*10^{-2}}{1.6} ]](https://tex.z-dn.net/?f=E%20%3D%20%200%20%20-%20%20%5Cfrac%7B0.0591%7D%7B2%7D%20%20%2A%20log%5B%5Cfrac%7B%202.00%2A10%5E%7B-2%7D%7D%7B1.6%7D%20%5D)
=> 