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Vladimir [108]
3 years ago
6

Why is it painful to lift a heavy load with a thin piece of string?

Physics
1 answer:
Aleksandr [31]3 years ago
5 0

Explanation:

A thin piece of string has lower force than of a heavy load.

When the load is being lifted, the force exerted by the load is much more greater than the string, which eventually hits our hands.

For example, a heavy bag. You tie a thin string to it and try to lift it. The force exerted by the bag will hit the string harder, reaching for your plams. As the thin string has less force, its reaction force is not enough to hit back the greater force. Also, the less the surface area, the more difficult the grip gets. But, if you attach a thick rope or belt, the force exerted my the bag is automatically minimized as the reaction force of the thick rope is near about the action force. Hence, greater the surface area, better the grip.

<em>*action force: force exerted by the bag</em>

<em>*reaction force: the force hit back by the rope</em>

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The amount of WORK done is determined by 2 factors.
RUDIKE [14]

Explanation :

Work is done when a force is applied to create a displacement on an object.

Thus, the work done depends on the two factors i.e.

(1) Applied force (F)

(2) Distance or displacement (d)

Mathematically, work done is W= F.s

It also depends on the angle between the force and the displacement.

        W=Fs\ cos\ \theta

For example,

A person carries a weight of 20 kg and lifts it on his head 1.5 m above the surface. So, the work done by him on the luggage will be:

W= F\times s

or

W=m\times g \times s

W=20\ kg\times 9.8\ m/s^2\times 1.5\ m

So, W=294\ Joules

Hence, the work done by him on the luggage is 294 Joules.

6 0
3 years ago
An alien spacecraft flies directly over a football stadium at a speed of 0.50c. if the proper length of the field is 100 yards,
Ivahew [28]
Go on way and you will get your answer


6 0
3 years ago
4) A drag racer starts her car from rest and accelerates at 10.0 m/s² for a distance of 400 m (1/4 mile). (a) How long did it ta
mel-nik [20]

Answer:

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3 0
3 years ago
A stream moving with a speed of 7.1 m/s reaches a point where the cross-sectional area of the stream decreases to one half of th
lana66690 [7]

Answer:

14.2 m/s

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let the cross section area at initial point be A₁

now area at the second point, A₂ = (1/2)A₁ = 0.5A₁

now, from the continuity equation, we have

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thus, on substituting the values, we get

A₁ × 7.1 = 0.5A₁ × v₂

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8 0
3 years ago
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