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ikadub [295]
3 years ago
11

If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th

e same conditions?2 CO (g) + O2 (g) ---> 2 CO2 (g)
a. 1.5 L
b. 3.0 L
c. 4.5 L
d. 6.0 L,
Chemistry
1 answer:
mr_godi [17]3 years ago
8 0

Answer:

The volume of CO2 produced is 6.0 L (option D)

Explanation:

Step 1: Data given

Volume of oxygen = 3.0 L

Carbon monoxide = CO = in excess

Step 2: The balanced equation

2 CO (g) + O2 (g) → 2 CO2 (g)

Step 3: Calculate moles of O2

1 mol of gas at STP = 22.4 L

3.0 L = 0.134 moles

Step 3: Calculate moles of CO2

For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

0.268 mol = 22.4 * 0.268 = 6.0 L

The volume of CO2 produced is 6.0 L

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Students find the pH of Substance A to be 2.1 and Substance B to be 4.4. They are told Substance C is less acidic than Substance
Slav-nsk [51]

Answer:

the range should be 2.2 to 4.3

Explanation:

I think so because the numbers at the left side of the scale from 1 are more acidic so as it increases it's still acidic but lesser so 1 is more acidic than 2 so I used 2.2 as the beginning of the range because it's less acidic than A even though its a greater number and 4.3 is lesser than 4.4 but its still greater on the scale. frankly speaking I don't feel so correct because it's in decimal so try and compare facts thank you

8 0
3 years ago
Phosphate buffers are commonly used in biological research. If a small amount of strong acid is added to a buffer solution that
lozanna [386]

Answer:

A) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly decrease.

Explanation:

A buffer is a solution which resists changes to its pH when a small amount of acid or base is added to it.

Buffers consist of a weak acid (HA) and its conjugate base (A–) or a weak base and its conjugate acid. Weak acids and bases do not completely dissociate in water, and instead exist in solution as an equilibrium of dissociated and undissociated species. When a small quantity of a strong acid is added to a buffer solution, the conjugate base, A-, reacts with the hydrogen ions from the added acid to form the weak acid and a salt thereby removing the extra hydrogen ions from the solution and keeping the pH of the solution fairly constant. On the other hand, if a small quantity of a strong base is added to the buffer solution, the weak acid dissociates further to release hydrogen ions which then react with the hydroxide ions of the added base to form water and the conjugate base.

For example, if a small amount of strong acid is added to a buffer solution that is 0.700 M H3PO4 and 0.700 M KH2PO4, the following reaction is obtained:

KH₂PO₄ + H+ ----> K+ + H₃PO₄

Therefore, [H₃PO₄] will increase, [KH₂PO₄] will decrease, and pH will slightly decrease.:

4 0
3 years ago
Where is a product found at the beginning or end of a chemical reaction?
olya-2409 [2.1K]
A reaction is when two or more pure substances combine with each other to form another identity of pure substances. In general from, it is written as:

A + B → C + D

The substances A and B are the reactants, while the substances C and D are the products. Therefore, in a reaction, the products are found at the end or right side of the reaction.
3 0
3 years ago
Which of the following describes a compound? (Hint: Carbon and oxygen both appear on the periodic table.)
Alekssandra [29.7K]

Answer:

A

Explanation:

a compound is a pure substance and A tells that

5 0
3 years ago
How many moles of potassium chloride (KCI) are in 252 mL of 0.33 mil/L KCI
Rom4ik [11]

Answer:

0.083 moles KCl

Explanation:

We have 252 mL of 0.33 M KCl. "M" is molarity, and it's measured in mol/L. Since we know the molarity is 0.33 mol/L, in order to find how many moles 252 mL is, we need to multiply our given volume by the molarity.

However, our given volume is in mL, so let's convert to L first by dividing 252 by 1000 (because there are 1000 mL in 1 L):

252/1000 = 0.252 L

Now, we can multiply 0.252 L by 0.33 mol/L to get moles since the L units will cancel out:

0.252 L * 0.33 mol/L = 0.08316

We have two significant figures here, so round 0.08316 to 0.083.

The answer is 0.083 moles.

Hope this helps!

7 0
3 years ago
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