Answer:
5.12 L
Explanation:
P1V1/T1 = P2V2/T2
1.71 atm *10.0L /100 K = 9.70 atm *x/290.29 K
x = 1.71 atm *10.0L*290.29K /(100 K * 9.70 atm)= 5.12 L
Following reaction takes place between LiOH and HNO3
LiOH + HNO3 → LiNO3 + H2O
Thus, 1 mole of LiOH reacts with 1 mole of HNO3 to form 1 mole of LiNO3.
Now,
Number of millimoles of LiOH consumed = <span>36.90 X 0.100 = 3.690
</span>∴Number of millimoles of HNO3 present = 3.690
<span>
Now, Molarity of HNO3 = </span>
![\frac{\text{number of millimoles of HNO3}}{\text{volume of solution (ml)}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Ctext%7Bnumber%20of%20millimoles%20of%20HNO3%7D%7D%7B%5Ctext%7Bvolume%20of%20solution%20%28ml%29%7D%7D%20)
=
![\frac{3.690}{50}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3.690%7D%7B50%7D%20)
= 0.0738 M
Thus, <span>
molarity of the HNO3 solution is 0.0738 M</span>
ºF = ºC x 1.8 + 32
ºF = 17 x 1.8 + 32
ºF = 30.6 + 32
= 62.6ºF
hope this helps!
2. 4, 6, 8 Represents valence electrons
Answer:
The different magnetic shielding effects of the carbonyl double bond in CH0, the CH₂ (a) and CH₂ (b) protons show different chemical shifts
Because the degree of shielding depends on electron density round the proton, the neighboring carbonyl group will increase this density in geranial form.
Now in CH₂ the electron density is increased around CH₂ (a) protons in neral form due to the carbonyl group, and thus it has a lower z values than the corresponding geranial form.
In the case of CH₃ (b) protons. thus they have lower z values and higher chemical shift than the corresponding nera form.
Explanation:
Solution
Due to the different magnetic shielding effects of the carbonyl double bond in CH0, the CH₂ (a) and CH₂ (b) protons show different chemical shifts.
Since the degree of shielding depends on electron density round the proton, the neighboring carbonyl group will increase this density in geranial form more in case of CH₃ (b) protons. thus they have lower z values and higher chemical shift than the equivalent nera form.
Similarly, the electron density is increased around CH₂ (a) protons in neral form due to the carbonyl group, and thus it has a lower z values than the equivalent geranial form.