Answer:
1.22 mol Ca
Explanation:
Molar mass (Ca)=40.1 g/mol
49.0 g* 1 mol/40.1 g ≈ 1.22 mol Ca
The answer is in the photo
Note that
1 mi = 1609.34 m = 1609.34 x 10⁶ um
1 h = 3600 s = 3600 x 10⁹ ns
Therefore the speed of the bug is
(3.0 mi/h)*(1609.34x10⁶ um/mi)*(1/3600x10⁹ h/ns)

Answer:
I think the answer is 6 A good luck!