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alexira [117]
3 years ago
8

1. How does protein substance in animal hide or skin be preserved from bacterial infection during tanning?

Chemistry
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

1. By being cured

2. To remove the silica impurities from haemetite

3. The cathode will be bronze while the anode will be the silver

4. i) Wastes from industrial processes

ii) Waste waters and sewage

iii) Dumping of wastes into water bodies

5) Three methods to reduce air pollution includes

i) Promote the use of recycled of materials

ii) Promote and use renewable sources of energy

iii) Limit activities that involve the burning of fuels such as encouraging the use of mass transit buses, preventing the occurrence of fires in forests

Explanation:

1. In order to preserve the proteins in the hides of animal skin from putrefaction they are cured with salt to remove by, osmotic pressure difference,  the water content present in the animal hide

2. To remove the silica impurities from haemetite

The calcium oxide obtained from the decomposition of calcium carbonate undergoes a chemical reaction with the sand impurities in the mineral, haematite, to form calcium silicate or s l a g

3. Electroplating involves charging the metal to be electroplated negatively that is making it the cathode and placing it in an electrolytic cell that has a solution of the metal ions containing the metal salts

Therefore, the bronze medal to be plated with silver will be made the cathode while the silver from which we obtain the silver ions will be made the anode

4. Three causes of water pollution includes

Wastes from industrial processes

Waste waters and sewage

Dumping of wastes into water bodies

5.  The major causes of air pollution are the oxides produced from the combustion of fossil fuels such as sulfur dioxide, carbon dioxide, carbon monoxide as well as chemical gases from industrial processes.

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Inessa [10]
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6 0
3 years ago
The bomb calorimeter in Exercise 102 is filled with 987g water. The initial temperature of the calorimeter contents is 23.32. A
Sholpan [36]

Answer:

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

-q_{combust} = q_{water} + q_{calori}

q_{combust} = heat of combustion of benzoic acid

q_{water} = heat energy released to water

q_{calori} = heat energy released to the calorimeter

Therefore,

-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})

1.056*26.42 = [0.987*4.18 + 6.66](T_{f} - 23.32)

27.8995 = [4.12566+6.660](T_{f} - 23.32)

(T_{f} - 23.32) = 27.8995/10.7857 = 2.587

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4 0
3 years ago
At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
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Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

We know, K_{p}=K_{c}(RT)^{\Delta n}

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and \Delta n is difference in sum of stoichiometric coefficient of products and reactants

Here \Delta n=(2)-(2+1)=-1 and T = 311 K

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Answer:

Explanation:

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2 years ago
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