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3 years ago

2. Find the weight of a person (on Earth) in Newtons if they have a mass= 55.0 kg.

Physics

1 answer:

adelina 88 [10]3 years ago

8 0

Answer:

539 N

Explanation:

Fg = mg

Step 1: Define

Fg = ?

m = 55.0 kg

g = 9.8 m/s²

Step 2: Substitute and Evaluate

Fg = 55.0 kg(9.8 m/s²)

Fg = 539 N

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What is Humpty Dumpty's momentum if he has a mass of 56kg and is walking to the wall at a rate of 3 m/s?

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Answer:

168

Explanation:

56 x 3

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3 years ago

Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t

Troyanec [42]

Answer:

The minimum coefficient of static friction for the box on the floor of the trunk is 0.54.

Explanation:

Given that,

Radius of the unbanked curve, r = 48 m

The speed of the car on the curve, v = 16 m/s

We need to find the minimum coefficient of static friction for the box on the floor of the trunk. It can be calculated by balancing the centripetal force and the force of gravity as :

$\mu mg=\dfrac{mv^2}{r}$

$\mu=\dfrac{v^2}{rg}$

$\mu=\dfrac{(16)^2}{48\times 9.8}$

$\mu=0.54$

So, the minimum coefficient of static friction for the box on the floor of the trunk is 0.54. Hence, this is the required solution.

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4 years ago

A helicopter lifts a 60 kg astronaut 17 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/

dimulka [17.4K]

Answer:

a) W = 10995.6 J

b) W = - 9996 J

c) Kf = 999.6 J

d) v = 5.77 m/s

Explanation:

Given

m = 60 Kg

h = 17 m

a = g/10

g = 9.8 m/s²

a) We can apply Newton's 2nd Law as follows

∑Fy = m*a ⇒ T - m*g = m*a ⇒ T = (g + a)*m

where T is the force exerted by the cable

⇒ T = (g + (g/10))*m = (11/10)*g*m = (11/10)*(9.8 m/s²)*(60 Kg)

⇒ T = 646.8 N

then we use the equation

W = F*d = T*h = (646.8 N)*(17 m)

W = 10995.6 J

b) We use the formula

W = m*g*h ⇒ W = (60 Kg)(9.8 m/s²)(-17 m)

⇒ W = - 9996 J

c) We have to obtain Wnet as follows

Wnet = W₁ + W₂ = 10995.6 J - 9996 J

⇒ Wnet = 999.6 J

then we apply the equation

Wnet = ΔK = Kf - Ki = Kf - 0 = Kf

⇒ Kf = 999.6 J

d) Knowing that

K = 0.5*m*v² ⇒ v = √(2*Kf / m)

⇒ v = √(2*999.6 J / 60 Kg)

⇒ v = 5.77 m/s

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4 years ago

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Answer:

Cost= 0.5 $

Explanation:

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m = mass of a substance (kg)

c = specific heat (units J/kg∙K)

∆ is a symbol meaning "the change in"

∆T = change in temperature (Kelvins, K)

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Energy = energy discharged or vented every hour= ρVc ΔT

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Q = 1.6 Kwh

$W=\frac{Q}{COP}$

Q = $\frac{1.6}{3.2} = 0.5kwh$

Cost = per unit cost x energy vent x no of hours

Cost = 0.1 x 0.5 x 10

Cost= 0.5 $

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4 years ago

In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu

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Answer:

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Explanation:

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3 years ago

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