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3 years ago

COMPLETE THE SENTENCE: "A sustainable material is ......

Physics

2 answers:

Helen [10]3 years ago

7 0

A sustainable process is one that you can keep on doing
without using anything up or wearing anything out.

FrozenT [24]3 years ago

5 0

Wood branches but do not cut off the stump only branches

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A 1.35 kg block at rest on a tabletop is attached to a horizontal spring having constant 19.8 n/m. the spring is initially unstr

Ket [755]

Horizontal force is applied to the object causing the spring to stretch. the acceleration of gravity is 9.8 m/s

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3 years ago

In your opinion, is "avoiding" an effective conflict management strategy? Why or why not?

soldi70 [24.7K]

In my personal opinion, avoiding in not an effective conflict management strategy. When you are avoiding a conflict, you are really just pushing it to the side and it will need to be dealt with sooner or later. Avoiding a conflict is also ammeter thing to do as well, you should take responsibility and handle any situation.

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3 years ago

Read 2 more answers

Which of the following is the best definition of a closed system?

lisov135 [29]

The answer is either

b A system in which Newton's Laws are valid

c A system in which there are no external forces.

Explanation:

not a, and not d

There are energy changes in a closed system.

A closed system obeys the conservation laws in its physical description.

4 0

3 years ago

A wave has a period of 2 seconds and a wavelength of 4 meters.Calculate its frequency and speed.

Lana71 [14]

F=l/t
f=4/2
f=2m/s

Hope this helps

3 0

3 years ago

Read 2 more answers

I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block

borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

$T = 2\pi \sqrt{\frac{m}{k} }$

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

$T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\$

Now, determine the amplitude of oscillation, A;

$E = \frac{1}{2} kA^2$

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

$E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A = \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm$

Therefore, the amplitude of the oscillation is 2.82 cm

8 0

3 years ago