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oksian1 [2.3K]
4 years ago
10

One liter of water at 10 degrees celsius is added to one liter of water at 80 degrees celsius. what is the final temperature of

the mixture?
Chemistry
1 answer:
notka56 [123]4 years ago
3 0
Find the average of these 2 temperatures, since they have the same volume.

(80 + 10) ÷ 2 = 90 ÷ 2 = 45°C

You can only use this method of averaging them out because they have the same volumes :)
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What is bias in an experiment?
eimsori [14]

a process where the scientists performing the research influence the results, in order to show a certain result

3 0
3 years ago
Read 2 more answers
How many control(s) are in an experiment
weqwewe [10]
You can have as many controls as necessary, But they must remain equal at all times in order to get the most accurate results
6 0
3 years ago
Which transformation could take place at the anode of an electrochemical cell? Which transformation could take place at the anod
mr_godi [17]

Answer:

None of the above could take place at the anode.

Explanation:

In a cell, a redox reaction takes place, so one substance must reduce (gain electrons), and others must oxidize (lose electrons). At the anode, the substance oxidizes, and at the cathode the substance reduces.

Thus, we need to find what transformation oxidation is happening. To this, let's calculate the oxidation number (nox) of the atoms. If it's increasing, and oxidation is happening, if it's decreasing, a reduction is happening.

O₂ to H₂O:

O2 is a simple substance, so it has nox = 0. In a compound, O has nox -2 and H +1, so the nox of O is decreasing.

Cr₂O₇⁻² → Cr⁺²:

O has nox -2, so let's call the nox of Cr as x:

2x +7*(-2) = -2

2x -14 = -2

x = +6

And Cr⁺² has nox +2, so it's reducing.

F₂ to F⁻:

F₂ is a simple substance, so F has nox 0, and F⁻ has nox -1, then it's reducing.

HAsO₂ to As:

H has nox +1, and O has nox -2, so calling x the nox of As:

+1 + x + 2*(-2) = 0

1 + x - 4 = 0

x = +3

And As is a simple substance, that has nox 0, the it's reducing.

Thus, none of them is oxidizing, and none of them could take place at the anode.

6 0
3 years ago
To cook in a dry heat is.<br> 1-Baking<br> 2-Broiling<br> 3-Boiling<br> 4-Sauteing
Degger [83]

Answer:

Baking

Explanation:

4 0
3 years ago
An unknown compound was found to have a percent composition as follows: 47.0%, 14.5 carbon, and 38.5 oxygen. What is its empiric
shusha [124]

 KCO₂

 K₂C₂O₄

Explanation:

Given parameters:

Percent composition:

             K = 47%

             C = 14.5%

             O = 38.5%

Molar mass of compound = 166.22g/mol

Unknown:

Empirical formula of compound = ?

Molecular formula of compound = ?

Solution:

The empirical formula of a compound is its simplest formula. Here is how to solve for it:

 

                                K                                C                           O

Percent

composition           47                               14.5                       38.5

Molar mass            39                                  12                           16

Number

of moles               47/39                         14.5/12                     38.5/16

moles                    1.205                          1.208                          2.4

Dividing

by smallest      1.205/1.205               1.208/1.205                      2.4/1.205

                                1                                  1                                        2

Empirical formula               KCO₂

Molecular formula

  This is the actual combination of the atoms:

          Molecular formula =   ( empirical formula of KCO₂)ₙ

 Molar mass of empirical formula = 39 + 12 + 2(16) = 83g/mol

      n factor = \frac{true molecular mass}{molar mas of empirical formula}

      n factor = \frac{166.22}{83} =  2

Molecular formula of compound = ( KCO₂)₂ = K₂C₂O₄

Learn more:

Empirical formula brainly.com/question/2790794

#learnwithBrainly

6 0
4 years ago
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