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zavuch27 [327]
3 years ago
13

A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou

lombs, what was the oxidation state of the manganese produced
Chemistry
1 answer:
qwelly [4]3 years ago
8 0

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = \frac{mass}{charge}

i.e Z = \frac{m}{Q} = \frac{0.225g}{1580C} = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ \frac{55}{valency} = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

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A region of metamorphic rock lies far beneath Earth’s surface. In time, which two ways can the rock make its way upward to Earth
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It can uplift slowly due to the pressure of Earth’s plates.

It can melt into magma and recrystallize as extrusive igneous rock.

8 0
4 years ago
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Using relative enthalpy and entropy values, determine how the process is affected after each of the following temperature or pre
lutik1710 [3]

The question is incomplete, the complete question is:

Using relative enthalpy and entropy values, determine how the process is affected after each of the following temperature or pressure changes? Consider that a more effective reaction produces more product or more product in a shorter amount of time.

Reaction: SO2 (g) + 2H2S (g) ↔ 3S(s) + 2H2O (g)

Substance | ΔG kJ/mol | ΔH kJ/mol

H2O(g) | -228.6 | -241.8

H2O(l) | -237.1 | -285.8

SO2(g) | -300.4 | -296.9

SO3(g) | -370.4 | -395.2

H2S(g) | -33.01 | -20.17

S(s) | 0 | 0

Categorize into: "More Effective" ~ "Less Effective" ~ "Equally Effective"

- Temp. decreases while maintaining container size

- Temp. increases while maintaining container size

- Pressure decreases while maintaining container size

- Pressure increases while maintaining container size

Answer:

Explanation:

ΔH∘rxn=ΔH∘f(products)−ΔH∘f(reactants)

ΔH∘rxn= [0+2(-241.8)] - [(-296.9) + 2(-20.7)]= -145.6KJ/mol

ΔG∘rxn=[(0+ 2(-228.6) -[(-300.4) + 2(-33.01)]= -90.78KJ/mol

The reaction is spontaneous since ΔG∘rxn is negative

The reaction is exothermic since ΔH∘rxn= negative

1) increase in pressure is less effective because it favours the reverse reaction.

2) increase in temperature is less effective since it favours the reverse reaction given that the reaction is exothermic in nature

3) decrease in pressure is more effective, it favours the forward reaction

4)Decrease in temperature is more effective because it favours the forward reaction.

5 0
3 years ago
NEED HELP ASAP WITH THESE QUESTIONS GIVING FAIR AMOUNT OF POINTS IF HELPED WITH ALL QUESTIONS Violet light has a wavelength of 4
scoray [572]

Answer:

a) 7.14e19 Hz

b) 2.298e-27 J

c) 2.793e-19 J; 7.117e9 nm

d) 7.5e14 Hz; 4.96e-19 J

e) 6.2947e-18 J; 31.6 nm

f) 2.21e-22 J

g) 7.1e-19 J; 1.1e15 Hz

h) 3.422e-19 J; 581 nm

i) 4.2e14 Hz

j) 1.92e8 m

k) 7.14e16 Hz; Ultraviolet

Explanation:

Frequency: ν       Wavelength: λ       Energy: E       Speed of light: C (3.00e8)       Planck's Constant: h (6.626e-34)

ν -> λ    λ = C/ν

λ -> ν    ν = C/λ

For either of these equations, wavelength must be converted to meters or nanometers, depending on the equation.

For ν -> λ, after doing the equation, convert the wavelength into nanometers by dividing by 1e-9.

For converting λ -> ν, convert the wavelength into meters by multiplying by 1e-9.

For energy: E = hν = hc/λ

Now that the setup is out of the way:

a) Violet light has a wavelength of 4.20 x 10-12 m. What is the frequency?

λ -> ν    ν = C/λ

\frac{3.00e8}{4.20e-12} = 7.14e19 Hz

b) A photon has a frequency (n) of 3.468 x 106 Hz. Calculate its energy

E = hν = hc/λ

(6.626e-34) (3.468e6) = 2.298e-27 J

c) Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 4.215 x 1014 Hz.

E = hν = hc/λ

(6.626e-34) (4.215e14) = 2.793e-19 J

ν -> λ    λ = C/ν

\frac{3.00e8}{4.215e14} = 7.117 m

\frac{7.117m}{1}*\frac{1nm}{1e-9m} = 7.117e9 nm

d) Calculate the frequency and the energy of blue light that has a wavelength of 400 nm  (h = 6.62 x 10-34 J-s).

λ -> ν    ν = C/λ

\frac{400 nm}{1} *\frac{1e-9m}{1nm} = 4e-7 m

\frac{3.00e8}{4e-7} = 7.5e14 Hz

E = hν = hc/λ

(6.626e-34) (7.5e14) = 4.96e-19 J

e) Calculate the wavelength and energy of light that has a frequency of 9.5 x 1015 Hz.

ν -> λ    λ = C/ν

\frac{3.00e8}{9.5e15} = 3.16e-8 m

\frac{3.16e-8m}{1}*\frac{1nm}{1e-9m} = 31.6 nm

E = hν = hc/λ

(6.626e-34) (9.5e15) = 6.2947e-18 J

f) A photon of light has a wavelength of 0.090 cm. Calculate its energy.

E = hν = hc/λ

Convert the wavelength from cm to meters:

\frac{0.090cm}{1} *\frac{1m}{100cm} = 9e-4 m

\frac{(6.626e-34)(3.00e8)}{9e-4} = 2.21e-22 J

g) Calculate the energy and frequency of red light having a wavelength of 2.80 x 10-5 cm.

E = hν = hc/λ

Convert the wavelength from cm to meters:

\frac{2.80e-5cm}{1} *\frac{1m}{100cm} = 2.8e-7 m

\frac{(6.626e-34)(3.00e8)}{2.8e-7} = 7.1e-19 J

λ -> ν    ν = C/λ

Convert the wavelength from cm to meters:

\frac{2.80e-5cm}{1} *\frac{1m}{100cm} = 2.8e-7 m

\frac{3.00e8}{2.8e-7} = 1.1e15 Hz

h) Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 5.165 x 1014 Hz.

E = hν = hc/λ

(6.626e-34) (5.165e14) = 3.422e-19 J

ν -> λ    λ = C/ν

\frac{3.00e8}{5.165e14} = 5.81e-7 m

\frac{5.81e-7m}{1}*\frac{1nm}{1e-9m} = 581 nm

i) The wavelength of green light from a traffic signal is centered at 7.20 x 10-5 cm. Calculate the frequency.

λ -> ν    ν = C/λ

Convert the wavelength from cm to meters:

\frac{7.20e-5 cm}{1} *\frac{1m}{100cm} = 7.2e-7 m

\frac{3.00e8}{7.2e-7} = 4.2e14 Hz

j) If it takes 1.56 seconds for radio waves (which travel at the speed of light) to reach the moon from Earth, how far away is the moon?

  All we want to do here is to convert frequency (speed) to wavelength (distance). This problem requires a bit of thought, but it isn't bad once you realize that frquency is speed and wavelength is distance. It becomes just like the other problems after that. Also, I'll leave this distance in meters, but I think you can figure out how to convert it if it wants it in another unit.

  One second is equal to 1 Hertz, so our frequency is 1.56 Hz.

ν -> λ    λ = C/ν

\frac{3.00e8}{1.56} = 1.92e8 m

  The actual distance from the earth to the moon via google is 3.84e7, but sometimes problems like this will mess with the numbers to make sure that you didn't just look up the answer. I'm still pretty sure that this is right, however.

k) Calculate the frequency of light that has a wavelength of 4.20 x 10-9m. Identify the type of electromagnetic radiation.

First, we convert wavelength to frequency, as normal:

λ -> ν    ν = C/λ

\frac{3.00e8}{4.20e-9} = 7.14e16 Hz

Then we identify the electromagnetic wave type. You can look up a conversion chart for these on google, but since our frequency is in the e15 - e17 range, this light is considered ultraviolet.

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4 years ago
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Answer:

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pls Mark my answer in brainlist and follow me

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