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zavuch27 [327]
3 years ago
13

A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou

lombs, what was the oxidation state of the manganese produced
Chemistry
1 answer:
qwelly [4]3 years ago
8 0

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = \frac{mass}{charge}

i.e Z = \frac{m}{Q} = \frac{0.225g}{1580C} = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ \frac{55}{valency} = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

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An uncharged atom of mercury has an atomic number of 80 and an atomic mass of 200. This atom has ________ protons, ________ neut
SCORPION-xisa [38]
<h3>Answer:</h3>

             This atom has 80 protons, 120 neutrons and 80 electrons.

<h3>Explanation:</h3>

Number of Protons:

                               As the number of protons present in the nucleus are equal to the atomic number therefore. As given, the atomic number is 80 therefore, Hg contains 80 protons respectively.

Number of Electrons:

                                 As given in statement, Hg is not carrying any type of charge. It means this atom is neutral in nature. Which means, it is carrying the same number of electrons as the number of protons in order to give a neutral atom. Therefore, it contains 80 electrons.

Number of Neutrons:

                                 Number of neutrons can be calculated using following formula,

                  No. of Neutrons  =  Atomic Mass - Number of Protons

As,

                                    Atomic Mass  =  200

So,

                                    No. of Neutrons  =  200 - 80

                                    No. of Neutrons  =  120

3 0
3 years ago
Classify lead: Select one: C = compound HE = heterogeneous mixture S = homogeneous mixture/solution E = element
Ira Lisetskai [31]

Lead is an E (element) and can be found on the periodic table.

5 0
3 years ago
Which condition can cause excessive pressure on the high side of a self contained active recovery device
murzikaleks [220]

Answer:

What can cause excessive pressure on the high side of an active self-contained recovery device? A closed recovery tank inlet valve or excessive air or other non condensables in the recovery tank (either A or B) Portable refillable tanks or containers used to ship recovered refrigerants must meet what standard(s)?

Explanation:

please mark me as brainliest thank you

5 0
3 years ago
A researcher studying the nutritional value of a new candy places a 4.10 g sample of the candy inside a bomb calorimeter and com
Ierofanga [76]
<h3>Answer:</h3>

5.078 Cal/g

<h3>Explanation:</h3>

We are given;

Mass of the sample of candy as 4.10 g

Change in temperature, °C = 2.1 °C

Heat capacity of the calorimeter, C = 41.50 kJ/K

We are required to calculate the nutritional Calories per gram of candy

Since the Candy sample was burnt

Then the heat lost by the candy is equivalent to the heat absorbed by the calorimeter.

Therefore, we need to calculate the heat energy absorbed by the calorimeter.

Quantity of heat = Heat capacity × Change in temperature

Q = C×Δt

Q = 41.50 kJ/K × 2.1 K

  = 87.15 kJ

Therefore;

The heat released by 4.10 g of candy is  87.15 kJ

Calories per gram = Heat energy ÷  mass of candy

But; 1 kJ = 4.186  Calories

Therefore;

Number of calories =  87.15 kJ ÷ 4.186 Claories/kJ

                                = 20.82 Calories

Hence, calories per gram = 20.83 Cal ÷ 4.10 g

                                          = 5.078 Cal per g

                                          = 5.078 Cal/g

Thus, the nutritional Calories per gram of candy is  5.078 Cal/g

3 0
4 years ago
Could someone help me with this. i am very confused.
adell [148]

Answer:

same tho

Explanation:

5 0
3 years ago
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