How many moles of oxygen atoms are present in 5
moles of Mg3(PO4)2
All you have to do is to create
a ratio between the molecule and the oxygen atom.
5 moles of Mg3(PO4)2 (4x2 moles
O/1 mole Mg3(PO4)2) = 40 moles of oxygen
I think your answer will be B. 273 k
According to Bohr's model of the atom, the higher the orbital in which the electrons are found, the higher their energy or excitation state. Therefore, the electrons with the least amount of energy are those at the lowest orbitals, which are closer to the nucleus.
These orbitals are characterized by 4 quantum numbers, namely the principal quantum number (n), orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms). The principal quantum number reflects the distance of the electrons from the nucleus with n=1 as the orbital closest to the nucleus. Thus, according to Bohr's model, electrons in the orbital with n=1 have the lowest energy.
Answer:1-methoxy-2,4-dinitrobenzene
Explanation:
The nitro groups are strongly electron withdrawing and promote nucleophilic substitution reactions where one of the original substituents is removed and replaced by a strong nucleophile such as the methoxy group. The mechanism of the reaction is attached below. The electron withdrawing nitrogroup assists the formation of the intermediate in the reaction as shown.