Answer:d
Explanation:
Given systems are state of matter and do not contain any heat instead Heat is required to change Phase or raise the temperature of the particular system.
For example 600 kg of ice at 
Heat Required to convert it to water at is
Where L=latent heat of Fusion 
Answer:
The correct answer option is C
Explanation:
In a balanced chemical reaction mass of the reactant are always equal to mass of the products. Also known as Law of Conservation of Mass which states that " mass can nor be created nor be destroyed in a chemical reaction."
So, the mass of the reactant will be equal to the mass of products.That is 120 grams.
Hence, the correct answer option(C).
Answer: Yes
Explanation:
does hot air rise
er substances, expands when heated and contracts when cooled. Because there is more space between the molecules, the air is less dense than the surrounding matter and the hot air floats upward. This is the concept used in the hot air balloons.
Answer:
Option C. 1.2 m
Explanation:
The following data were obtained from the question:
horizontal velocity (u) = 2.08 m/s
Horizontal distance (s) = 0.96 m
Height (h) of the table =?
Next, we shall determine the time taken for the lab cart to get to the ground. This can be obtained as follow:
horizontal velocity (u) = 2.08 m/s
Horizontal distance (s) = 0.96 m
Time (t) =?
s = ut
0.96 = 2.08 × t
Divide both side by 2.08
t = 0.96 / 2.08
t = 0.5 s
Finally, we shall determine the height of the table as illustrated below:
Time (t) = 0.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) of the table =?
h = ½gt²
h = ½× 9.8 × 0.5²
h = 4.9 × 0.25
h = 1.2 m
Thus, the height of the table is 1.2 m
Answer:
t´ = 2,5 h
Explanation:
Dado que a velocidades "comparables" a la velocidad de la luz, los principios de la física deben ser tratados a la luz de los conceptos relativistas, es necesario aplicar el factor de Lorentz al tiempo que los estudiantes tomaran como base para la elaboración de su examen-
El factor de Lorentz γ = 1 / √1 - (v²/c²)
En ese factor c es la velocidad de la luz y v es la velocidad a la que se mueve el móvil ( en este caso la nave espacial que va a 0,6 *c )
La otra consideración que hay que tomar en cuenta es que cuando se tienen dos sistemas inerciales con velocidades relativas comparables a la velocidad de la luz, las coordenadas espaciales ( y el tiempo que es la cuarta coordenada ) se relacionan según:
(Movimiento exclusivo en la dirección del eje x )
x´ = ( x - vₓt )*γ y´= y z´ = z t´ = ( t - vₓ/c² ) *γ
Donde las coordenadas s distinguen por ´ y sin ´ para identificar a los dos sistemas, luego entonces:
t´ ( tiempo en la nave espacial )
t´ = [ t - (0,6*c/c² ] *γ ⇒ t´ = t - 0,36/c / √1 - (0.6*c)²/c²
Dado que t = 2 h y que la velocidad de la luz c es 300000 km/s expresada en horas es 300000*3600 = 108*10⁷,el numerador se puede aproximar a 2 horas
t´ = 2 /√ 64*10⁻²
t´ = 2 / 0,8 h
t´ = 2,5 h
