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3 years ago

14

A student pulls a cart across the floor with a force of 45 N. If the cart travels 10 m, how much work does the cart do on the st

udent?

1 answer:

bixtya [17]3 years ago

6 0

I'm assuming we're applying the standard Integral form of the calculation of work. The solution is provided in the image.

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Which image shows an example of the strong nuclear force in action?

dusya [7]

i think this is the incomplete page that you are showing but the answer is

:-

<h2><u>B</u></h2>

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3 years ago

An electron has an initial velocity of (19.0 j + 18.0 k) km/s and a constant acceleration of (3.00 ✕ 1012 m/s2)i in a region in

asambeis [7]

Answer:

$E=(-17.08 i +7.2 j -7.6 k )N/C$

Explanation:

$v= (19.0j+18.k)km/s$

$a=3.0x10^{13}m/s^2$

$\beta= 400x10{-6}T$

Electron information needed to solve the question:

$m_e=9.11x10^{-31}kg$

$q=-1.6x10{-19}C$

$F=F_E+F_B=q*(E+Vx \beta)$

$F=m*a$

$m*a=q*(E+Vx\beta)$

$E=\frac{m*a}{q}-(Vx\beta )$

$E=\frac{9.11x10{-31}kg*3.0x10^{12}m/s^2}{-1.6x10{-19}C}-[(19.0x10^3mj+18.0x10^3m)xi(400x10^{-6}T)]$

$E=-i17.08N/C-[7.6(-k)+7.2(j)]N/C$

$E=(-17.08 i +7.2 j -7.6 k )N/C$

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2 years ago

Which phase of cell division is shown?

dalvyx [7]

Answer:

what was the answer

Explanation:

im taking the quiz and could use some help

6 0

2 years ago

At its closest point, Mercury is approximately 46 million kilometers from the sun. What is this distance in AU?

alina1380 [7]

1 astronomical unit 1 AU = 1.4960 * 10^11 meters
it is the average distance between earth and sun
mercury to sun distance is = 46,000,000 * 1000 meters
= 4.6 * 10^9 meters = 4.6 * 10^9 / 1.4960 * 10^11 AU
= 3.0.74 / 100 = 0.0374 AU

5 0

3 years ago

Read 2 more answers

A roller coaster accelerates from 0 m/s to 25 m/s in 5 seconds. Determine the acceleration of the roller coaster.

pashok25 [27]

Acceleration = change of velocity / time taken = 25/5 = 5 m/s/s

5 0

3 years ago