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sweet [91]
2 years ago
10

An astronaut brings a cube from the earth to the moon. What is true about the inertial mass and weight of the cube?

Physics
1 answer:
Luden [163]2 years ago
6 0

When an astronaut brings a cube from the Earth to the Moon, the inertial mass remains constant, but the weight decreases.

<h3>What is the difference between mass and weight?</h3>

Mass of the body is defined as the amount of matter a body have. It is denoted by m and its unit is kg.

Weight is defined as the amount of force an object expert on the surface. It is given as the product of mass and the gravitational pull.

When an astronaut brings a cube from the Earth to the Moon, the inertial mass remains constant, but the weight decreases.Because the value of the gravitational acceleration is different on the moon.

Hence, option D is correct.

To learn more about the mass, refer to the link;

brainly.com/question/19694949

#SPJ4

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Could I please get some help on this question I don’t understand .
Oksana_A [137]

Answer:

12.5 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 8 m

Final velocity (v) at 8 m above the lowest point =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

The velocity of the roller coaster at 8 m above the lowest point can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 8)

v² = 0 + 156.8

v² = 156.8

Take the square root of both side

v = √156.8

v = 12.5 m/s

Therefore, the velocity of the roller coaster at 8 m above the lowest point is 12.5 m/s.

5 0
3 years ago
A: hydrogen and hydrogen b: copper and copper c: copper and oxygen Rank the above bonds in terms of increasing bond strength. Ch
pashok25 [27]

Answer: Copper and oxygen

Explanation:

Copper and oxygen shares the ionic bond. As we know that ionic bond is the most strongest bond. Here is the order:

Hydrogen bond< Metallic bond< Ionic bond.

That means order in terms of increasing bond strength is :

Hydrogen and hydrogen< Copper and copper< Copper and oxygen.

5 0
3 years ago
our lab partner wears a new pair of sneakers to lab and, rather than performing the required experiments, you decide to measure
Dafna1 [17]

Answer:

The coefficient of static friction between your partner and the floor is 0.55

Explanation:

Given:

Mass m = 59 Kg

Frictional force F_{s}  = 318.3 N

From the formula of frictional force,

 F_{s} = \mu_{s} mg

Where \mu _{s} = coefficient of static friction, g = 9.8 \frac{m}{s^{2} }

Put the above values and find the coefficient of static friction.

318.3 = \mu_{s} \times 59 \times 9.8

\mu_{s} = 0.55

Therefore, the coefficient of static friction between your partner and the floor is 0.55

4 0
3 years ago
Some element can be either solid or liquid. At the melting point, the liquid has 8 × 10-22 J more enthalpy per atom than the sol
OlgaM077 [116]

Answer:

481.76 J/mol

133.33 K

Explanation:

N_A = Avogadro's number = 6.022\times 10^{23}

Change in enthalpy is given by

\Delta H=8\times 10^{-22}\times 6.022\times 10^{23}\\\Rightarrow \Delta H=481.76\ J/mol

Entropy is given by

\Delta S=6\times 10^{-24}\times 6.022\times 10^{23}\\\Rightarrow \Delta S=3.6132\ J/mol K

Latent heat of fusion is given by

L_f=\Delta H\\\Rightarrow L_f=481.76\ J/mol

The latent heat of fusion is 481.76 J/mol

Melting point is given by

T_m=\dfrac{L_f}{\Delta S}\\\Rightarrow T_m=\dfrac{8\times 10^{-22}\times 6.022\times 10^{23}}{6\times 10^{-24}\times 6.022\times 10^{23}}\\\Rightarrow T_f=133.33\ K

Melting occurs at 133.33 K

3 0
3 years ago
A dentist’s drill starts from rest. After 3.20 s of constant angu-lar acceleration, it turns at a rate of 2.51 3 104 re v/m i n.
Gekata [30.6K]

Answer:

ΔTita = 4205.6 rad

Explanation:

w_{i} means initial angular velocity, which is 0 rev/min

w_{f} means final angular velocity, which is 2.513*10^{4}rev/min

t means time t= 3.20 s

one revolution is equivalent to 2πrad so the final angular velocity is:

w_{f} = (2π/60) *2.513*10^{4} rad/s

w_{f}= 2628.5 rad/s

so the angular acceleration, α will be:

α = 2628.5 rad/s / 3.20 s

a = 821.40 rad/s^{2}

so the rotational motion about a fixed axis is:

w^{2} _{f} =w^{2} _{i} + 2αΔTita    where ΔTita is the angle in radians

so now find the ΔTita the subject of the formula

ΔTita = \frac{w^{2} _{f}-w^{2} _{i}  }{2a}

ΔTita = ((2628.5)^{2} - (0 rev/min)^{2}) / 2* 821.40

ΔTita = 4205.6 rad

7 0
3 years ago
Read 2 more answers
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