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Gala2k [10]
3 years ago
8

What happens to the acceleration when the velocity is zero

Physics
1 answer:
Ulleksa [173]3 years ago
7 0
<h2>Answer:</h2>

It's easy to fall into the temptation to say that when the velocity is zero, then the acceleration is also zero. But wait! To answer this question we need to bring out the concept of instantaneous velocity. This type of velocity stands for a specific moment, a specific instant of time, that is, t=1, \ t=2, \ t=3, \ t=3.2 \ t=4.5. If so, then acceleration may not be zero when velocity is zero. For example, suppose you throw an object upward, when it is at the top of the travel the instantaneous velocity is zero because it changes from positive to negative value and there is a moment when it must be zero, but yet there is a constant acceleration by the Earth's gravity at that moment. Even though the velocity at that stationary moment is zero, it doesn't imply the acceleration must be zero, so it has a value and in this case is -9.8m/s^{2}

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I need help with these. Please show workings<br>​
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Answer:

Imp = 25 [kg*m/s]

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Explanation:

In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.

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(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})

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v₁ = initial velocity = 0 (initially at rest)

F = force = 5 [N]

t = time = 5 [s]

v₂ = velocity after the momentum [m/s]

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2)

(m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})\\(0.075*0)+(30*0.05)=(0.075*v_{2})\\v_{2}=20 [m/s]

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A projectile is fired from the ground at a velocity of 30.0 m/s, 35.0 º from the horizontal. What is the maximum height the proj
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Answer:

Vy = V sin theta = 30 * ,574 = 17.2 m/s

t1 = 17.2 / 9.8 = 1.76 sec to reach max height

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(URGENT) A ball rolls off a ledge. Its velocity is 7.70m/s in a horizontal direction. It falls on the floor 1.60m below the ledg
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Answer:

the horizontal distance is 4.355 meters

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The computation of the horizontal distance while travelling in the air is shown below:

Data provided in the question is as follows

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R = horizontal direction

Based on the above information

As we know that

R = u × time

where,

Time = \sqrt{\frac{2H}{g} }

So,

= 7.70\times \sqrt{\frac{2\times 1.60}{10} }

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hence, the horizontal distance is 4.355 meters

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Differences between sublimation and condensation
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The difference between sublimation and condensation is that

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