Transverse wave, movement in which all focuses on a wave sway along ways at right edges to the course of the wave's development. Surface swells on water, seismic S (auxiliary) waves, and electromagnetic (e.g., radio and light) waves are instances of transverse waves. Waves come in two assortments.
Answer:
6.3 m/s
Explanation:
m = mass of the block = 1.10 kg
k = spring constant of the spring
x = stretch in the spring = 0.2 m
t = time taken by block to come to zero speed first time = 0.100 s
T = Time period of oscillation
Time period of oscillation is given as
T = 2t
T = 2 (0.1)
T = 0.2 s
Time period is also given as


k = 1084.6 N/m
v = maximum speed of the block
using conservation of energy
Maximum kinetic energy = Maximum spring potential energy
(0.5) m v² = (0.5) k x²
m v² = k x²
(1.10) v² = (1084.6) (0.2)²
v = 6.3 m/s
λ = 2 m.
The easiest way to solve this problem is using the equation of frecuency of a wave f = v/λ, where v is the velocity of the wave, and λ is the wavelength.
To calculate the wavelength of a microwave light travels through a liquid, it moves at a speed of 2.2 x 10⁸ m/s. If the frecuency of the light wave is 1.1 x 10⁸ Hz, we have to clear λ from the equation f = v/λ:
f = v/λ -------> λ = v/f
λ = 2.2 x 10⁸ m/s / 1.1 x 10⁸ Hz
λ = 2 m (wavelength of the microwave)
Given:
u = 10⁵ m/s, the entrance velocity
v = 2.5 x 10⁶ m/s, the exit velocity
s = 1.6 cm = 0.016 m, distance traveled
Let a = the acceleration.
Then
u² + 2as = v²
(10⁵ m/s)² + 2*(a m/s²)*(0.016 m) = (2.5 x 10⁶ m/s)²
0.032a = 6.25 x 10¹² - 10¹⁰ = 6.24 x 10¹²
a = 1.95 x 10¹⁴ m/s²
Answer: 1.95 x 10¹⁴ m/s²
It would mostly depend on its weight