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harina [27]
3 years ago
6

Click the Run Now button to start the simulations. Select "Many rays" and click the Screen checkbox. You should see a lamp and a

black screen. a. Examine the light rays that are emerging from the lamp. Are the rays near the light source diverging or converging? Where do the light rays change direction? b. For the light rays that do bend, think about which way those rays would travel if they had not bent. Explain why the lens must be a converging lens.
Physics
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

Answer explained below

Explanation:

(a) The rays are diverging near the lens. They change the direction when they passed through the converging lens

(b) If the light rays don't bend they will move away from the optical (principal axis) as the other waves are moving.

(c) If we decrease the distance between lens and light source, most of the rays diverge and no ray converges on the screen even after passing through the lens. Here is a screenshot.

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Yo-Yo man releases a yo-yo from rest and allows it to drop, as he keeps the top end of the string stationary. The mass of the yo
patriot [66]

To solve this problem it is necessary to use the conservation equations of both kinetic, rotational and potential energy.

By definition we know that

KE + KR = PE

Where,

KE =Kinetic Energy

KR = Rotational Kinetic Energy

PE = Potential Energy

In this way

\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh

Where,

m = mass

v= Velocity

I = Moment of Inertia

\omega = Angular velocity

g = Gravity

h = Height

We know as well that \omega = v/r for velocity (v) and Radius (r)

Therefore replacing we have

\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh

[tex]h= \frac{1}{2} \frac{v^2}{g} +\frac{1}{2} \frac{I}{mg}(\frac{v}{r})^2[/tex]

h= \frac{1}{2}v^2 ( \frac{1}{g} +\frac{I}{mg}\frac{1}{r^2} )

h= \frac{1}{2}0.75^2 ( \frac{1}{9.8} +\frac{2.9*10^{-5}}{(0.056)(9.8)}\frac{1}{(0.0064)^2} )

h = 0.3915m

Therefore the height must be 0.3915 for the yo-yo fall has a linear speed of 0.75m/s

6 0
3 years ago
Who made the Earth? I don't know if it was God for sure, but I would like an answer to help me out.
Nina [5.8K]
Scientists believe that um the big bang created the earth
5 0
3 years ago
Read 2 more answers
Which of the following statements describe P-waves? Select the two correct answers
oksian1 [2.3K]

Answer:

A.They alternately compress and pull apart the particles in matter.

B. They are the first waves detected after an earthquake.

Explanation:

P-waves, also known as a compressional wave is the wave that shakes the ground in the same and opposite direction of the wave i.e. back and forthe motion of the ground. They compress and pull apart the material alternatively. The disturbances due to these waves have small magnitude thus making them non destructive. These waves travel at faster speed as compared to other seismic waves and thus help in detecting the earthquake. These wave can travel through liquid, solid and gases.

5 0
3 years ago
If forces acting on an object are unbalanced, the object could experience a change in , direction, or both.
pashok25 [27]
I would think both because you cannot predict what will happen because it is unbalanced you are basically letting the earth take control of the object. 
hope that helped?!
:)
7 0
3 years ago
A 2.26 cm tall object is placed in 18.6 cm in front of a convex lens. The focal length
Gnesinka [82]

Answer:

the image is -38.7 cm from the lens

Explanation:

We use the lens equation which says  

$\frac{1}{u}+\frac{1}{v}=\frac{1}{f}  $

where u is the distance to the object, v is the distance to the image, and f  is the focal length.

Now, in our case

u =18.6cm,

v= 35.8cm,

f = 35.8cm;

therefore,

$\frac{1}{18.6}+\frac{1}{v}=\frac{1}{35.8}  $

$\frac{1}{v}=\frac{1}{35.8}-\frac{1}{18.6}  $

\boxed{v=-38.7cm}

where the negative sign indicates that the image is virtual and on the same side of the lens as the object.

7 0
3 years ago
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