It is a fundamental property of a material and tells how strongly the material is opposing the current. The resistance is related to resistivity by the relation, R=ρAl. The resistivity of a material depends on temperature. It increases with the increase in temperature and decreases with the decrease in temperature.HOPE THIS HELPS!!!
Answer:
SO4
Explanation:
I'm not sure if you're asking for more than one answer but S04 is one of them, you can search it up if you don't believe me
ion with the subscript of the atoms in a polyatomic ion. There is only ONE Cu and ONE S04, so get the charge for the Cu based on the S04. The formula is S04 , and there is only ONE S04 2, so Cu's charge here must be +2 for the compound to have an overall charge of zero. = copper (Il) ion S04 = sulfate ion then CuS04 = copper (Il) sulfate
Answer:
E = 75 J
Explanation:
First, we will calculate the total power consumed by the five lamps:

Now, the energy supply can be calculated as follows:

where,
E = Energy = ?
t = time = 5 s
Therefore,
E = (15 W)(5 s)
<u>E = 75 J</u>
Answer:
A) At point 1, local acceleration = 0.5 m/s²
At point 2, local acceleration = 1.0 m/s²
B) Average Eulerian convective acceleration over the two points in the cross section shown = 0.5 m/s²
This value is positive indicating an increase in velocity and acceleration kf the fluid as the cross sectional Area of flow reduces.
Explanation:
Local acceleration at those points is the instantaneous acceleration at those points and it is given as
a = dv/dt
At point 1, v₁ = 0.5 t
a₁ =dv₁/dt = 0.5 m/s²
At point 2, v₂ = 1.0 t
a₂ = dv₂/dt = 1.0 m/s²
b) Average Eulerian convective acceleration over the two points in the cross section shown = (change of velocity between the two points)/time
Change of velocity between the two points = v₂ - v₁ = 1.0t - 0.5t = 0.5 t
Time = t
Average acceleration = 0.5t/t = 0.5 m/s²
This value is positive indicating an increase in velocity and acceleration kf the fluid as the cross sectional Area of flow reduces.
Answer:
2 charges of electron (2C)
Explanation:
I = Q/t
2 = Q/1
Q = 2×1= 2C
Q = 2 charge of electron