All categories

4 years ago

Please Help Me

Physics

1 answer:

JulijaS [17]4 years ago

7 0

1. a=Δv/Δt=(v-vo)/t=(0-25)/5=-25/5=-5 m/s²

The "-" sign shows us that the car has a slow motion

2.a=Δv/Δt=(v-vo)/t=(10-0)/4=10/4=2,5 m/s²

3.they do not have acceleration because they go at constant speed

You might be interested in

Two equal charges are separated by 3.7x10^-10m. The force between the charges has a magnitude of 2.37x10^-3 N. What is the magni

Alla [95]

Answer:

Charge on two particles is given as

$q = 1.89 \times 10^{-16} C$

Explanation:

As we know that the electrostatic force between two charges is given by formula

$F = \frac{Kq_1q_2}{r^2}$

so we will have

$q_1 = q_2 = q$

$r = 3.7 \times 10^{-10} m$

$F = 2.37 \times 10^{-3} N$

so we have

$2.37 \times 10^{-10} = \frac{(9 \times 10^{9})(q)(q)}{(3.7 \times 10^{-10})^2}$

$q = 1.89 \times 10^{-16} C$

3 0

3 years ago

I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52

Oduvanchick [21]

Answer:

28.1 m/s

Explanation:

$u_x$ = Initial velocity of the fish = 1.52 m/s

y = Height of the bird = 40 m

$a_y$ = Acceleration in y axis = $9.81\ \text{m/s}^2$

$u_y$ = Initial velocity in y axis = 0

$y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}$

$v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}$

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction $u_x=v_x=1.52\ \text{m/s}$

Resultant velocity is given by

$v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}$

The fish is moving at a velocity of 28.1 m/s when it hits the water.

6 0

3 years ago

A plan to budget time for studying and activities is referred to as? a study routine study habits study skills a study schedule

ad-work [718]

Answer:

a study schedule

Explanation:

5 0

3 years ago

HELP: I’ve been stuck on this problem for a while now.

Arlecino [84]

Answer:

a.work done=force *displacement

=500N*46m

=23000 Joule

b.power=work done/time taken

=23000/25

=920 watt

c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)

=60kg*9.8m/s*14m

=8232 joule

Explanation:

3 0

4 years ago

Riddle :what month of the year has 28 days ?

Romashka [77]

Answer: all of them lol

Explanation:

5 0

3 years ago