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3 years ago

How can resistance be useful and where can they be useful?

1 answer:

3 0

-- Resistance can be useful among the population of a repressive government.
Although it can be dangerous for those who resist, it can also exert pressure
against the regime to alter its repressive practices.

-- Resistance can also be useful in electronic circuits. "Lumped" components with
known numerical values of resistance are used to divide voltage, limit current, and
dissipate controlled amounts of electrical energy.

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Leap years _____. happen because the Earth revolves around the sun in less than 365 days make up for the extra one-fourth day th

anzhelika [568]

The Earth takes (365 and 1/4) days to orbit the sun. That's the length of our 'year'.

Since it's not really possible to make our calendar a quarter of a day longer every year, we make the calendar a <u><em>whole</em></u> day longer every 4 years.

So "Leap years" make up for the extra one-fourth day the Earth takes to orbit the sun.

7 0

4 years ago

Which characteristics is common to the four outer planets in out solar system ?

Lubov Fominskaja [6]

I think the answer is B

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3 years ago

Read 2 more answers

A typical wall outlet voltage in the United States is 120 volts. Personal MP3 players require much smaller voltages, typically 4

alexgriva [62]

Answer:

Number of turns on the secondary coil of the adapter transformer is 10.

Explanation:

For a transformer,

$\frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }$

where $V_{s}$ is the voltage induced in the secondary coil

$V_{p}$ is the voltage in the primary coil

$N_{s}$ is the number of turns of secondary coil

$N_{p}$ is the number of turns of primary coil

From the given question,

$\frac{487*10^{-3} }{120}$ = $\frac{N_{s} }{2464}$

⇒ $N_{s}$ = $\frac{2462*487*10^{-3} }{120}$

= 9.999733

∴ $N_{s}$ = 10 turns

5 0

3 years ago

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Can anyone plzzzz answer this question... Cuz it's really urgent....

nlexa [21]

The fastest in speed of sound is steel. The slowest in speed of sound is oxygen. Hope this helped! I don't really know how to answer this but by looking at the table it looks like this can be one of the conclusions.

4 0

3 years ago

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A football kicked in front of a goal post at an angle of 45 degree to the ground just clear the top by of the post 3m high. Calc

Firlakuza [10]

Answer:

A. 10.84 m/s

B. 1.56 s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 45°

Maximum height (H) = 3 m

Acceleration due to gravity (g) = 9.8 m/s²

Velocity of projection (u) =?

Time (T) taken to hit the ground again =?

A. Determination of the velocity of projection.

Angle of projection (θ) = 45°

Maximum height (H) = 3 m

Acceleration due to gravity (g) = 9.8 m/s²

Velocity of projection (u) =?

H = u²Sine²θ / 2g

3 = u²(Sine 45)² / 2 × 9.8

3 = u²(0.7071)² / 19.6

Cross multiply

3 × 19.6 = u²(0.7071)²

58.8 = u²(0.7071)²

Divide both side by (0.7071)²

u² = 58.8 / (0.7071)²

u² = 117.60

Take the square root of both side

u = √117.60

u = 10.84 m/s

Therefore, the velocity of projection is 10.84 m/s.

B. Determination of the time taken to hit the ground again.

Angle of projection (θ) = 45°

Velocity of projection (u) = 10.84 m/s

Time (T) taken to hit the ground again =?

T = 2uSine θ /g

T = 2 × 10.84 × Sine 45 / 9.8

T = 21.68 × 0.7071 / 9.8

T = 1.56 s

Therefore, the time taken to hit the ground again is 1.56 s.

7 0

3 years ago