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Alexxandr [17]
3 years ago
9

What is absolute zero? What is the temperature of absolute zero on the Kelvin and Celsius scales?

Physics
2 answers:
vredina [299]3 years ago
7 0

Answer:

0 Kelvin

Explanation:

(Educere/Founder's Education Answer)

salantis [7]3 years ago
6 0

Answer:

Absolute zero = 0 K or - 273°C

Explanation:

Absolute zero :

 When the entropy and enthalpy of the ideal system reach at the minimum value then the temperature at that condition is known as absolute zero condition.

Absolute temperature is the minimum temperature in the temperature scale.The value of absolute zero is 0 K.

We know that

\dfrac{C-0}{100}=\dfrac{K-273}{100}=\dfrac{F-32}{180}

F=Temperature in Fahrenheit scale

K=Temperature in Kelvin scale

C=Temperature in degree Celsius scale

When  K = 0

\dfrac{C-0}{100}=\dfrac{K-273}{100}

\dfrac{C-0}{100}=\dfrac{0-273}{100}

C= - 273°C

Absolute zero = 0 K or - 273°C

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Two 30 uC charges lie on the x-axis, one at the origin and the other at 9 m. A third point is located at 27 m. What is the poten
alukav5142 [94]

Answer:

25000 V

Explanation:

The formula for potential is

V = Kq/r

Potential at B due to the charge placed at origin O

V1 = K q / OB

V_{1}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{27}

V1 = 10000 V

Potential at B due to the charge placed at A

V2 = K q / AB

V_{2}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{18}

V2 = 15000 V

Total potential at B

V = V1 + V2 = 10000 + 15000 = 25000 V

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3 years ago
Brainliest for first answer that’s not a link or a troll
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Answer:

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5 0
3 years ago
Joe and Max shake hands and say goodbye. Joe walks east 0.50 km to a coffee shop, and Max flags a cab and rides north 3.45 km to
timama [110]

Answer:

3.486 km

Explanation:

Suppose Joe and Max's directions are perfectly perpendicular (east vs north). We can calculate their distance at the destinations using Pythagorean theorem:

s = \sqrt{J^2 + M^2}

where J = 0.5 km and M= 3.45 km are the distances between Joe and Max to their original parting point, respectively. s is the distance between them.

s = \sqrt{0.5^2 + 3.45^2} = \sqrt{12.1525} = 3.486 km

8 0
3 years ago
If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potent
Zina [86]

Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

N= 1.8*10^16 electrons

B. Power= I x v

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3 years ago
A skydiver accelerates from REST at 9.8 m/s² for the first 5m of their fall. Calculate their final speed. (Give your answer to 2
Kaylis [27]

Answer:

The final speed is 9.89 m/s.

Explanation:

Initial speed of skydiver is 0 as it was rest.

Acceleration of the skydiver is 9.8 m/s²

It accelerates for the first 5 m of their fall.

It is required to find their final speed. Let v is the final speed. It can be calculated using third equation of motion.

v^2-u^2=2as

Here, u = 0

a = 9.8 m/s²

s = 5 m

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So, the final speed is 9.89 m/s.

5 0
3 years ago
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