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Alexxandr [17]
3 years ago
9

What is absolute zero? What is the temperature of absolute zero on the Kelvin and Celsius scales?

Physics
2 answers:
vredina [299]3 years ago
7 0

Answer:

0 Kelvin

Explanation:

(Educere/Founder's Education Answer)

salantis [7]3 years ago
6 0

Answer:

Absolute zero = 0 K or - 273°C

Explanation:

Absolute zero :

 When the entropy and enthalpy of the ideal system reach at the minimum value then the temperature at that condition is known as absolute zero condition.

Absolute temperature is the minimum temperature in the temperature scale.The value of absolute zero is 0 K.

We know that

\dfrac{C-0}{100}=\dfrac{K-273}{100}=\dfrac{F-32}{180}

F=Temperature in Fahrenheit scale

K=Temperature in Kelvin scale

C=Temperature in degree Celsius scale

When  K = 0

\dfrac{C-0}{100}=\dfrac{K-273}{100}

\dfrac{C-0}{100}=\dfrac{0-273}{100}

C= - 273°C

Absolute zero = 0 K or - 273°C

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kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 is the mass of the first mosquito

u_1 = 0 is the initial velocity of the mosquito

m_2 = 50 m_1 is the mass of the raindrop

u_2 = 8.4 m/s is the initial velocity of the raindrop

v is the final combined velocity of the raindrop+mosquito

Re-arranging the equation and substituting, we find:  

m_1 u_1 + 50 m_1 u_2 = (m_1 + 50 m_1) v\\50 m_1 u_2 = 51 m_1 v\\50 u_2 = 51 v\\v=\frac{50}{51}u_2 = \frac{50}{51}(8.4)=8.2 m/s

Learn more about momentum here:

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Answer:

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A ship's wheel has a moment of inertia of 0.930 kilogram·meters squared. The inner radius of the ring is 26 centimeters, and the
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We can use the formula of the moment of inertia given by:

r\cdot F=I\alpha

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\begin{gathered} r\cdot F=(-0.26\times314+290\times0.32)=92.8-81.64=11.16 \\ I=0.930 \\ so,_{\text{ }}solve_{\text{ }}for_{\text{ }}\alpha: \\ \alpha=\frac{r\cdot F}{I} \\ \alpha=\frac{11.16}{0.930} \\ \alpha=\frac{12rad}{s^2} \end{gathered}

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