Solution : As they have uniform composition throughout they are considered as homogeneous mixture. Both samples are mixture of two metals (gold and palladium) thus are alloys.
Answer:
The answer to your question is below
Explanation:
2.- 6
3.- Carbon
4.- These electrons can be share to obtain stability.
5.- Protons, electrons
6.- electron cloud
7.- I and III
8.- 1
9.- 8A
10.- 4
11.- F
12.- F
13.- F
14.- T
15.- T
16.- T
17.- T
18.- T (I can not read the question but I think is true)
Answer:
0.01917 m^3/kg.
Explanation:
Given:
P = 15 MPa
= 1.5 × 10^4 kPa
T = 350 °C
= 350 + 273
= 623 K
Molar mass of water, m = (2 × 1) + 16
= 18 g/mol
= 0.018 kg/mol
R = 0.4615 kPa·m3/kg·K
Using ideal gas equation,
P × V = n × R × T
But n = mass/molar mass
V = (R × T)/P
V/M = (R × T)/P × m
= (0.4615 × 623)/1.5 × 10^4
= 0.01917 m^3/kg.
Answer:
Hope this helps :D
Explanation:
Metal: Aluminum and Copper
Non-Metal: Hydrogen and Flourine
Acid: Sulfuric Acid and Phosphoric Acid
Alkali Metals: Hydrogen and Lithium
Compounds: Water and Carbon Dioxide
Elements: Carbon and Oxygen