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QveST [7]
3 years ago
14

Is the following chemical equation balanced? 2Na + 2H2O 2NaOH + H2

Chemistry
2 answers:
Mumz [18]3 years ago
8 0

yes because you have 2 H 2Na 2O on both sides


Harman [31]3 years ago
6 0

Answer : Yes, the given chemical reaction is balanced equation.

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given chemical reaction is,

2Na+2H_2O\rightarrow 2NaOH+H_2

In this reaction, there are 2 atoms of sodium, 4 atoms of hydrogen and 2 atoms of oxygen are present on both side of the reaction. So,

This chemical reaction is a balanced reaction because in this reaction, the number of atoms of sodium, hydrogen and oxygen are balanced on the side of the reaction.

Hence, yes the given chemical reaction is balanced equation.

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SVETLANKA909090 [29]

<u>Answer:</u> The final concentration of potassium nitrate is 5.70\times 10^{-6}M

<u>Explanation:</u>

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of potassium nitrate (solute) = 0.360 g

Molar mass of potassium nitrate = 101.1 g/mol

Volume of solution = 500.0 mL

Putting values in above equation, we get:

\text{Molarity of }KNO_3=\frac{0.360\times 1000}{101.1\times 500.0}\\\\\text{Molarity of }KNO_3=7.12\times 10^{-3}M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2          .......(1)

  • <u>Calculating for first dilution:</u>

M_1\text{ and }V_1 are the molarity and volume of the concentrated KNO_3 solution

M_2\text{ and }V_2 are the molarity and volume of diluted KNO_3 solution

We are given:

M_1=7.12\times 10^{-3}M\\V_1=10mL\\M_2=?M\\V_2=500.0mL

Putting values in equation 1, we get:

7.12\times 10^{-3}\times 10=M_2\times 500\\\\M_2=\frac{7.12\times 10^{-3}\times 10}{500}=1.424\times 10^{-4}M

  • <u>Calculating for second dilution:</u>

M_2\text{ and }V_2 are the molarity and volume of the concentrated KNO_3 solution

M_3\text{ and }V_3 are the molarity and volume of diluted KNO_3 solution

We are given:

M_2=1.424\times 10^{-4}M\\V_2=10mL\\M_3=?M\\V_3=250.0mL

Putting values in equation 1, we get:

1.424\times 10^{-4}\times 10=M_3\times 250\\\\M_3=\frac{1.424\times 10^{-4}\times 10}{250}=5.70\times 10^{-6}M

Hence, the final concentration of potassium nitrate is 5.70\times 10^{-6}M

8 0
3 years ago
Titration Lab Day 2 Data Sheet help?
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Consider the reaction below. 2Al2O3 4Al + 3O2 What is the mole ratio of oxygen to aluminum?
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3 years ago
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There are 50 fish in the pond that have tags. You catch 25 fish, and 5 of them have tags. What is the best estimate of the numbe
sergeinik [125]

Answer: 250


Explanation:


You work this problem by using proportions.


A proportion is the equalization of two ratios.


Here you assume that the ratio of fish with tags to total fish that you catch is the same than the ratio of fish with tags to total fish in the pond.


Mathematically:

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Solve for x:

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A carbohydrate comes from a chain of carbon atoms with an H2O associated with each other 
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