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QveST [7]
3 years ago
14

Is the following chemical equation balanced? 2Na + 2H2O 2NaOH + H2

Chemistry
2 answers:
Mumz [18]3 years ago
8 0

yes because you have 2 H 2Na 2O on both sides


Harman [31]3 years ago
6 0

Answer : Yes, the given chemical reaction is balanced equation.

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

The given chemical reaction is,

2Na+2H_2O\rightarrow 2NaOH+H_2

In this reaction, there are 2 atoms of sodium, 4 atoms of hydrogen and 2 atoms of oxygen are present on both side of the reaction. So,

This chemical reaction is a balanced reaction because in this reaction, the number of atoms of sodium, hydrogen and oxygen are balanced on the side of the reaction.

Hence, yes the given chemical reaction is balanced equation.

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When a chemical reaction is run in aqueous solution inside a calorimeter, the temperature change of the water (and Ccal) can be
Yakvenalex [24]

Answer:

The total change in enthalpy for the reaction is - 81533.6 J/mol

Explanation:

Given the data in the question;

Reaction;

HCl + NaOH → NaCl + H₂O

Where initial temperature is 21.2 °C and final temperature is 28.0 °C. Ccal is 1234.28 J

Moles of NaOH  = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol

Moles of HCl = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol

so, 0.0500 moles of H₂O produced

Volume of solution = 50.mL  +  50.mL  = 100.0 mL

Mass of solution m = volume × density = 100.0mL × 1.0 g/mL = 100 g

now ,

Heat energy of Solution q= (mass × specific heat capacity × temp Δ) + Cal

we know that; The specific heat of water(H₂O) is 4.18 J/g°C.

so we substitute

q_soln = (100g × 4.18 × ( 28.0 °C - 21.2 °C) ) + 1234.28

q_soln = 2842.4 + 1234.28

q_soln = 4076.68 J

Enthalpy change for the neutralization is ΔH_{neutralization}

ΔH_{neutralization} = -q_soln / mole of water produced

so we substitute

ΔH_{neutralization} = -( 4076.68 J ) / 0.0500 mol  

ΔH_{neutralization} = - 81533.6 J/mol

Therefore, the total change in enthalpy for the reaction is - 81533.6 J/mol

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Answer:

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Answer:

Explanation:

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840g

Volume:

7 cm x 4 cm  x 10 cm = 280 cm^3

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