HELP!! 50 POINTS! PLEASE ANSWER AND EXPLAIN WHY:

In the laboratory you dissolve 12.3 g of chromium(ii) sulfate in a volumetric flask and add water to a total volume of 375. ml.

valentinak56 [21]

Hope it cleared your doubt.

4 0

3 years ago

What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, c2h6? in this reaction,

Vitek1552 [10]

Balance equation for combustion of ethane will be:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

To balance the equation:

1. Balance the number of carbon atom on both side:

C₂H₆(g) + O₂(g)--------> CO₂(g) + H₂O(g)

1. balance the number of carbon on both side, as in reactant there are 2 but in product one,

so , multiply the CO₂, by 2 in the product.

2. Balance the number of hydrogen on both side as in reactant the number of hydrogen is 3 but in product it is 6 so, multiplythe number of H₂O by 3,

so multiply the number of H₂O by 3 in product.

3. Balance the number of oxygen on both side , as 1 and 2 step increases the number of oxygen and it becomes 7 , so to balance the number of oxygen on both side by mutiplying the number of O₂ by 7/2 in reactant .

4. Now, doubling the equation will give balance equation that is:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

8 0

3 years ago

Which base is the strongest for the given [H+]?

AURORKA [14]

The answer is 10-12. The relationship of pH and [H+] is pH = -lg[H+]. And the higher pH, the stronger base is. So the strongest base has the lowest concentration of H+.

8 0

3 years ago

Zinc metal reacts with copper sulfate through the following

morpeh [17]

Answer:

26.9

Explanation:

5 0

2 years ago

Which of these methods could be used to separate an insoluble solid from a soluble solid? Melting the mixture and then using a f

I am Lyosha [343]

Answer : The correct option is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.

Explanation :

"The given mixture contains a soluble solid and an insoluble solid.

When water is added to this mixture, the soluble solid will get dissolved in water whereas the insoluble solid will remain as it is.

This will give us a heterogeneous mixture where we can see 2 distinct phases , one containing the dissolved solid and the other having undissolved solid.

In order to separate these 2 phases, we can use a simple filtration method.

When the mixture is filtered, we will get solution having soluble solid and the insoluble solid will remain on the filter paper.

This will separate the 2 solids.

To regenerate the dissolved solid, we can evaporate the water by heating it. This will give us back our original soluble solid.

Therefore, the only option that is consistent with this method is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid"

8 0

3 years ago