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GuDViN [60]
3 years ago
13

Structure of isobutyl formate

Chemistry
1 answer:
Aliun [14]3 years ago
4 0

Answer:

Isobutyl formate (2-methylpropyl methanoate) is an organic ester with the chemical formula C5H10O2. Used for flavor and fragrance because of its odor.

Explanation:

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A sample of gas occupies a volume of 10.5 L when the pressure is 14.3 psi. Use Boyle’s Law to calculate the pressure (psi) when
Nutka1998 [239]

Answer: 17.6psi

Explanation:

V1 = 10.5 L

P1 = 14.3 psi

V2 = 8.55L

P2 =?

P1V1 = P2V2

14.3 x 10.5 = P2 x 8.55

P2 = (14.3 x 10.5) / 8.55

P2 = 17.6psi

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3 years ago
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Which element has 32 protons in its nucleus? <br> phosphorus <br> cobalt<br> germanium<br> sulfur
eduard
<span>Germanium is the element that has 32 protons in its nucleus.</span>
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3 years ago
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How many atoms of Oxygen are there in 3 C1207?
natka813 [3]

Answer:

9 atoms

Explanation:

Explanation: In 1 formula unit of Al(NO3)3 , there are (clearly!) 9 atoms of oxygen, 3 nitrogen atoms, and 1 aluminum atom. I have gone on before that the mole ( NA , Avogadro's number) is simply a much larger number, i.e. NA = 6.022×1023 .

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2 years ago
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Can a physical or chemical change the amount of matter present
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5 0
3 years ago
For a reaction A + B → products, the following data were collected. Experiment Number Initial Concentration of A (M) Initial Con
Afina-wow [57]

Answer:

Rate constant k = 1.57*10⁻⁵ s⁻¹

Explanation:

Given reaction:

A\rightarrow B

Expt    [A] M        [B] M         Rate [M/s]

1          3.40         4.16           1.82*10^-4

2         4.59         4.16           3.32*10^-4

3.        3.40          5.46          1.82*10^-4

Rate = k[A]^{x}[B]^{y}

where k = rate constant

x and y are the orders wrt to A and B

To find x:

Divide rate of expt 2 by expt 1

\frac{3.32*10^{-4} }{1.82*10^{-4} } =\frac{[4.59]^{x} [4.16]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\x =2

To find y:

Divide rate of expt 3 by expt 1

\frac{1.82*10^{-4} }{1.82*10^{-4} } =\frac{[3.40]^{x} [5.46]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\y =0

Therefore: x = 2, y = 0

Rate = k[A]^{2}[B]^{0}

To find k

Use rate for expt 1:

k = \frac{Rate1}{[A]^{2} } =\frac{1.82*10^{-4}M/s }{[3.40]^{2} } =1.57*10^{-5} s-1

6 0
2 years ago
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