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mr Goodwill [35]
3 years ago
12

An aqueous solution has a hydroxide-ion concentration of 1.0 x 10-3M. What is the pH of the solution?

Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0
11 with pemdas, you have to multiply all by 3
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Marissa blows up balloons for a party. She decides how big or small to make each balloon. Why does the air she blows into each b
Oxana [17]
Air is it gas so it fills its container, the balloon, completely.
5 0
3 years ago
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

4 0
3 years ago
5 QUESTIONS PLZ ANSWER ASAP<br><br> SCIENCE
sweet-ann [11.9K]
A. Plastic is a good insulator.
3 0
3 years ago
Read 2 more answers
Calculate the volume of 2.65 moles of CO2 gas at STP.
Harman [31]

Answer:

The volume is 59, 3 liters. See the explanation below, please

Explanation:

STP conditions (standard) correspond to 273K of temperature and 1 atm of pressure. These values are used and the volume is calculated, according to the formula:

PV = nRT

1 atm x V= 2, 65 moles x 0, 082 l atm/K mol x 272 K

V= 2, 65 moles x 0, 082 l atm/K mol x 272 K/1 atm = 59, 3 liters

6 0
3 years ago
How many moles of agcl are contained in 244 ml of 0.135 magcl solution? the density of the solution is 1.22 g/ml?
spin [16.1K]
Since we are only asked for the number of moles, we don't need the information of density. The concentration is expressed in terms of 0.135 M AgCl or 0.135 moles of AgCl per liter solution. The solution is as follows:

Moles AgCl = Molarity * Volume
Moles AgCl = 0.135 mol/L * 244 mL * 1 L/1000 mL
<em>Moles AgCl = 0.03294 mol </em>
3 0
3 years ago
Read 2 more answers
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