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mr Goodwill [35]
3 years ago
12

An aqueous solution has a hydroxide-ion concentration of 1.0 x 10-3M. What is the pH of the solution?

Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0
11 with pemdas, you have to multiply all by 3
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how are ionic bonds formed? a. by the disintegration of one or more electronsb. by the sharing of one or more electrons between
Greeley [361]

The correct answer is: by the transfer of one or more electrons from one atom to another.

6 0
4 years ago
The label on a bottle of medicine reads​ "Each 5 mL teaspoonful contains​ glucose, 1.87​ g; levulose, 1.87​ g; and phosphoric​ a
Alexandra [31]

(a) 43.6 mg; (b) 520 mg

(a) <em>Mass of phosphoric acid (PA) in a dose </em>

Mass of PA = 2 tsp × (21.8 mg PA/1 tsp) = 43.6 mg PA

(b) <em>Mass of PA in the bottle </em>

<em>Step 1</em>. Convert <em>ounces to millilitres </em>

Volume = 4 oz × (30 mL/1 oz) = 120 mL

<em>Step 2.</em> Calculate the mass of PA

Mass of PA = 120 mL × (21.8 mg PA/5 mL) ≈ 520 mg PA

4 0
4 years ago
Which produces the greatest number of ions when one mole dissolves in water?
Arada [10]
~Hello there!

Your question: Which produces the greatest number of ions when one mole dissolves in water?

Your answer: Na2SO4<span> can dissociate into three ions, whereas the other choices produce only two ions (or in the case of sucrose, none) when dissolved in water.

Any queries ^?

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7 0
4 years ago
Bobota
navik [9.2K]

Answer:

chemical stability

Explanation:

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4 0
3 years ago
Calculate the number of milliliters of 0.753 M KOH required to precipitate all of the Pb2+ ions in 135 mL of 0.775 M Pb(NO3)2 so
MrRa [10]

Answer:

278 ml of KOH.

Explanation:

The equation for the reaction is: Pb(NO3)2(aq) + 2KOH(aq) --> Pb(OH)2(s) + 2KNO3(aq)

Pb(NO3)2:

Half ionic equation:

Pb(NO3)2(aq) --> Pb2+ + 2NO3^-

Pb(OH)2 --> Pb2+ + 2OH-

Volume = 135 mL

Molar concentration = 0.775 M

Number of moles = molar concentration * volume

= 0.775 * 0.135

= 0.105 mol of Pb(NO3)2

Since 1 mole of Pb(NO3)2 reacted with 2 moles of KOH to give 1 mole of Pb2+ (Pb(OH)2).

By stoichiometry,

Number of moles of KOH = 0.105 * 2

= 0.21 mol

Molar concentration = number of moles/volume

Volume = 0.21/0.753

= 0.278 l

To ml, 0.278 l * 1000 ml/1l

= 278 ml of KOH.

3 0
3 years ago
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