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3 years ago

What are the two types of stoichiometry?

Chemistry

2 answers:

julsineya [31]3 years ago

8 0

Two types of stoichiometry are; molar mass and coefficients from balanced equation.

pav-90 [236]3 years ago

6 0

Grams and moles of a single chemical.
coefficients from balanced equation - to convert between moles of one chemical and moles of a different chemical.

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Select the correct answer.<br> What happens as you decrease the temperature of a solution?

shepuryov [24]

Answer:

the number of solute particles increases

3 0

3 years ago

To be able to see a measurable effect, your boiling point elevation must be at least 1.00°C. Knowing that the Kb of water is 0.

ale4655 [162]

Answer : The mass of calcium chloride (in g) needed is, 1.92 grams.

Explanation : Given,

Boiling point of elevation constant $(K_b)$ for water = $0.512^oC/m$

Mass of water (solvent) = $Density\times Volume=1.00g/mL\times 26.63mL=26.63g=0.02663kg$

Molar mass of $CaCl_2$ = 110.98 g/mole

Formula used :

$\Delta T_b=i\times K_b\times m\\\\\Delta T_b=i\times K_b\times\frac{\text{Mass of }CaCl_2}{\text{Molar mass of }CaCl_2\times \text{Mass of water in kg}}$

where,

$\Delta T_b$ = change in boiling point = $1.00^oC$

i = Van't Hoff factor = 3 (for electrolyte)

$K_b$ = boiling point constant for water

m = molality

Now put all the given values in this formula, we get

$1.00^oC=3\times (0.512^oC/m)\times \frac{\text{Mass of }CaCl_2}{110.98g/mol\times 0.02663kg}$

$\text{Mass of }CaCl_2=1.92g$

Therefore, the mass of calcium chloride (in g) needed is, 1.92 grams.

4 0

3 years ago

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c

gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.

Al³⁺ + 3 e⁻ → Al

We can establish the following relations:

1 Ampere = 1 Coulomb / second
The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
1 mole of Al is produced when 3 moles of electrons circulate
The molar mass of Al is 26.98 g/mol.

The mass of aluminum produced under these conditions is:

$90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al$

6 0

4 years ago

Titaium oxside is often added to food to color it white. If a jelly bean contains approximately 1.28x10-5 moles of TiO2, how man

PIT_PIT [208]

Answer:

1.02 × 10⁻³ g

Explanation:

Step 1: Given data

Number of moles of titanium (IV) oxide in 1 jelly bean (n): 1.28 × 10⁻⁵ moles

Step 2: Calculate the mass (in grams) corresponding to 1.28 × 10⁻⁵ moles of TiO₂

To convert moles to mass, we need a conversion factor. In this case, it is the molar mass of TiO₂: 79.87 g/mol.

1.28 × 10⁻⁵ mol TiO₂ × 79.87 g TiO₂/1 mol TiO₂ = 1.02 × 10⁻³ g TiO₂

6 0

3 years ago

What is the element found in Group 17 Period 4?

faust18 [17]

Answer:

Bromine is found in Group 17, Period 4 on the periodic table.

3 0

3 years ago