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stiv31 [10]
3 years ago
10

Which element has the largest atomic radii in the 3rd period of the periodic table?

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

Sodium (Na)

Explanation:

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The element rhenium (Re) exists as two stable isotopes and 18 unstable isotopes. Rhenium-185 has in its nucleus
sweet [91]

Answer:

d. 75 protons, 110 neutrons

Explanation:

In an isotope, the number next to the number of the atom is the mass number (Protons + neutrons). Rhenium has as atomic number 75, that means Rhenium has <em>75 protons</em>. As atomic mass, 185, is the sum of protons and neutrons, number of neutrons is:

185 - 75 = <em>110 neutrons</em>

<em />

Thus, right answer is:

<em>d. 75 protons, 110 neutrons </em>

<em />

8 0
3 years ago
____________J/g. Degree C
abruzzese [7]

Answer:

0.417 J/g'C

Explanation:

8 0
3 years ago
Explain how mass out 10 mL of milk
kirill [66]
Hi,

mL are smaller than liters. So milk should be liters, right? Yeah it should. If yiu put milk on a scale, it would go down bc it is so heavy. If it was not as heavy, it would be a different story here. Think of it that way.
8 0
3 years ago
Two cars travel next to each other. One speedometer reads
Yanka [14]

Answer:

The pair of arrows which represents the relationship of speeds of the two cars is;

The second option as shown in the attached drawing

Explanation:

The given parameters are;

The reading on the speedometer of one car = 20 m/s

The reading on the speedometer of the other car = 72 km/h = 20 m/s

The blue arrow = 20 m/s

Therefore, given that the speeds of both cars are equal (20 m/s = 72 km/h = 20 m/s),  the pair of arrows that represent the relationship of speeds of the two cars is two equal length blue arrows which is the second option

The attached diagram showing the pair of arrows that represents the relationship of speeds of the two cars is drawn using Microsoft Visio.

4 0
3 years ago
Given the balanced equation representing a reaction:
sleet_krkn [62]
4Al(s) + 3O2(g) --> 2Al2O3(s)    This is the balanced.
From the equation:

 4 moles of Al required 3 moles of O2 to produce 2 moles of Al2O3
 
3 moles of O2 reacted with 4 moles of Al to produce 2 moles of Al2O3
1 mole of O2 reacted with 4/3 moles of Al to produce 2/3 moles of Al2O3  (Divide by 3)
4.5 moles of O2 reacted with (4/3 *4.5) moles of Al to produce (2/3*4.5) moles of Al2O3

4.5 moles of O2 reacted with 6moles of Al to produce  3moles of Al2O3

(3) is the answer.  6 mol of Al.
7 0
3 years ago
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