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Vlad [161]
3 years ago
7

Dos cargas muy pequeñas de masas iguales m

Physics
1 answer:
NemiM [27]3 years ago
3 0

Answer:

b)A partir de dicha expresión encontrar el ángulo a en

función de m, L y q cuando a < 5º.

Explanation:

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The skater is has a mass of 75 kg. Find the total Potential energy of the skater at the top of the ramp at 6 m.
olga_2 [115]
Epot= mgh= 75*9,81*6= 4415 j
5 0
3 years ago
Select the star life cycle that is accurate.
Veseljchak [2.6K]

Answer:

B according to the picture

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8 0
3 years ago
To apply Problem-Solving Strategy 12.2 Sound intensity. You are trying to overhear a most interesting conversation, but from you
Ivenika [448]

Answer:

r₂ = 0.316 m

Explanation:

The sound level is expressed in decibels, therefore let's find the intensity for the new location

            β = 10 log \frac{I}{I_o}

let's write this expression for our case

           β₁ = 10 log \frac{I_1}{I_o}

           β₂ = 10 log \frac{I_2}{I_o}

           

          β₂ -β₁ = 10 ( log \frac{I_2}{I_o} - log \frac{I_1}{I_o})

          β₂ - β₁ = 10 log \frac{I_2}{I_1}

          log \frac{I_2}{I_1} = \frac{60 - 20}{10} = 3

           \frac{I_2}{I_1} = 10³

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having the relationship between the intensities, we can use the definition of intensity which is the power per unit area

           I = P / A

           P = I A

the area is of a sphere

          A = 4π r²

           

the power of the sound does not change, so we can write it for the two points

          P =  I₁ A₁ =  I₂ A₂

          I₁ r₁² = I₂ r₂²

we substitute the ratio of intensities

          I₁ r₁² = (10³ I₁ ) r₂²

         r₁² = 10³ r₂²

         

         r₂ = r₁ / √10³

         

we calculate

          r₂ = \frac{10.0}{\sqrt{10^3} }

          r₂ = 0.316 m

8 0
3 years ago
The children at the local park think the slide is too slow. There is too much fiction. What could you do to decrease the amount
igor_vitrenko [27]
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7 0
4 years ago
What are the differences and relationships between speed, velocity, and acceleration
melamori03 [73]

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3 0
3 years ago
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