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Vlad [161]
3 years ago
7

Dos cargas muy pequeñas de masas iguales m

Physics
1 answer:
NemiM [27]3 years ago
3 0

Answer:

b)A partir de dicha expresión encontrar el ángulo a en

función de m, L y q cuando a < 5º.

Explanation:

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A tin can whirled on the end of a string moves in a circle because
Ilya [14]

Answer:

There is an inward force acting on the can

Explanation:

This inward force is known as Centripetal force and it is responsible for making the can whirl on the end of a string in circle and it is also directed towards the center around which the can is moving.

8 0
3 years ago
(f) What do you mean by: (i) 1 J energy (ii) 1 W power​
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Explanation:

Watts are defined as 1 Watt = 1 Joule per second (1W = 1 J/s)

which means that 1 kW = 1000 J/s. A Watt is the amount of energy (in Joules) that an electrical device (such as a light) is burning per second that it's running.

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3 years ago
4. A 100-kg soldier in the Arctic is coasting on his ice skates at a speed of 3.0 m/s. He fires 35 bullets directly forward from
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Answer:

The gunner must apply 240 N  to the gun to stop it from moving back.

Explanation:

6 0
3 years ago
The Atomic Mass of an element is
dedylja [7]

Answer:

C) A ratio based on the mass of a carbon-12 atom

Explanation:

For each element, there is a characteristic number of protons, this number represent a type of atom and its called the atomic number

On the other hand we have the number of neutrons, and for one element which difers only on the number of neutrons, we have different isotopes from one element.

Together, protons and neutrons define the mass number

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6 0
4 years ago
Read 2 more answers
A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p
a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

Given;

initial velocity of the body, u = 78.4 m/s

at maximum height (h) the final velocity of the body (v) = 0

The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h =  ¹/₂gt²

2h = gt²

t² = 2h/g

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 313.6}{9.8} }\\\\t = 8 \ s

4 0
3 years ago
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