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4 years ago

What is kinetic energy

Physics

1 answer:

Elena L [17]4 years ago

7 0

Answer:

energy which a body possesses by virtue of being in motion.

Explanation:

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Why does a heated mirror not become misty and stays clear

Elena L [17]

A mirror only mists because the air is hot and the mirror is cold and if it is heated than the steam wont make the mirror become misty....
hope this helps :D

7 0

3 years ago

Read 2 more answers

. The inner and outer surfaces of a 4-m × 7-m brick wall of thickness 30 cm and thermal conductivity 0.69 W/m-K are maintained a

Anni [7]

Answer:

$\frac{dQ}{dt} = 966 W$

Explanation:

As we know that the rate of heat transfer due to temperature difference is given by the formula

$\frac{dQ}{dt} = \frac{KA(\Delta T)}{L}$

here we know that

$K = 0.69 W/m-K$

A = 4 m x 7 m

thickness = 30 cm

temperature difference is given as

$\Delta T = 20 - 5 = 15 ^oC$

now we have

$\frac{dQ}{dt} = \frac{(0.69W/m-K)(28 m^2)(15)}{0.30}$

$\frac{dQ}{dt} = 966 W$

4 0

3 years ago

A body is traveling at 5.0 m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion s

loris [4]

To solve this problem it is necessary to apply the concepts related to the conservation of momentum and conservation of kinetic energy.

By definition kinetic energy is defined as

$KE = \frac{1}{2} mv^2$

Where,

m = Mass

v = Velocity

On the other hand we have the conservation of the moment, which for this case would be defined as

$m*V_i = m_1V_1+m_2V_2$

Here,

m = Total mass (8Kg at this case)

$m_1=m_2 =$ Mass each part

$V_i =$ Initial velocity

$V_2 =$ Final velocity particle 2

$V_1 =$ Final velocity particle 1

The initial kinetic energy would be given by,

$KE_i=\frac{1}{2}mv^2$

$KE_i = \frac{1}{2}8*5^2$

$KE_i = 100J$

In the end the energy increased 100J, that is,

$KE_f = KE_i KE_{increased}$

$KE_f = 100+100 = 200J$

By conservation of the moment then,

$m*V_i = m_1V_1+m_2V_2$

Replacing we have,

$(8)*5 = 4*V_1+4*V_2$

$40 = 4(V_1+V_2)$

$V_1+V_2 = 10$

$V_2 = 10-V_1$ (1)

In the final point the cinematic energy of EACH particle would be given by

$KE_f = \frac{1}{2}mv^2$

$KE_f = \frac{1}{2}4*(V_1^2+V_2^2)$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$ (2)

So we have a system of 2x2 equations

$V_2 = 10-V_1$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$

Replacing (1) in (2) and solving we have to,

200J=\frac{1}{2}4*(V_1^2+(10-V_1)^2)

PART A: $V_1 = 10m/s$

Then replacing in (1) we have that

PART B: $V_2 = 0m/s$

8 0

3 years ago

A 4.00-kg mass and a 9.00-kg mass are being held at rest against a compressed spring on a frictionless surface. When the masses

IgorLugansk [536]

Answer:

B) 0.500 m/s West

brainlist answer

4 0

3 years ago

Whihc radiations treat cancer is it a)beta b)alpha c)gamma d) all

Lena [83]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Treatment.

Basically according to the theory, GAMMA rays are used to treat the cancer.

c.) GAMMA RADIATIONS

6 0

4 years ago